Question

我是php的新手....对于下面提到的条件的plzz帮助。我有桌子。

表1 - 文献

Org_id |    literature_id|  name    |   type
-------------------------------------------------
---------------------------------------------
1      |    1            |  xxxx    | yyyyy
-------------------------------------------------
---------------------------------------------
2      |     2           |xxxx      |Yyyyy
-------------------------------------------------
---------------------------------------------

表2 - 生物

Bio_id  |literature_id| title1     | title2         |  Org_id
------------------------------------------------------------------
------------------------------------------------------------------
1       |   1         | xxxxxx     | Marian species |   1
------------------------------------------------------------------
------------------------------------------------------------------
2       |   1         |  xxxx      | Yyyyy          |   2
------------------------------------------------------------------
------------------------------------------------------------------

表3-生物地理学

Com_id  |literature_id| title1  |title2 |Org_id
------------------------------------------------------------------
------------------------------------------------------------------
1       |      2      | xxx     |yyyy   |1
------------------------------------------------------------------
------------------------------------------------------------------
2       |       2     | xxxx    |Yyyyy  |2
------------------------------------------------------------------
------------------------------------------------------------------

表4- common_name

    $result1 = mysql_query("SELECT lit.literature_id,  lit.title1, lit.title2
                        FROM lit
    INNER JOIN Organism  on lit.literature_id = Organism.literature_id
                        WHERE organism_id='$org1'
                        UNION ALL
                        SELECT lit.literature_id,  lit.title1, lit.title2 
                        FROM lit
                        INNER JOIN biogeography  on lit.literature_id = biogeography.literature_id
                        WHERE organism_id='$org1'
                        UNION ALL
                        SELECT lit.literature_id,  lit.title1, lit.title2
                        FROM lit
                        INNER JOIN ecology  on lit.literature_id = ecology.literature_id
                        WHERE organism_id='$org1'

                        ");
    while($row = mysql_fetch_row($result1)) {
                        echo "
                        <td>$row[0]</td>
                        <td><i><b>'$row[1]',
                        '$row[2]'</i></b><br>

                        </td>
                        <td>$row[8]</td>

                                </tr>";

result image

如上表所示，表中有文献和组织表的详细信息，bio，com表以文献_id的形式参考文献。现在我想从所有表中取出那些literature_id到文献表中获取文献和显示的详细信息。

实施例： - 有机体id'1'有来自表Organism，Biogeography，common_name的参考文献_id 1,1,2。现在我想显示org_id'1'（$ org1）的所有参考文献及其文献详情。

怎么做？以及如何删除重复出现的文献_id ??因为它只会在显示记录时重复。（详情将与literature_id的文献相同）。

我使用下面的代码执行相同的操作，但我的输出可以在结果图像中看到。这是错误的，因为记录正在重复;当我显示记录时，我不想重复。请帮帮我....

代码是：

{{1}}

Answer 1

试试这个：

$result1 = mysql_query("SELECT lit.literature_id,  lit.title1, lit.title2
                        FROM lit
    INNER JOIN Organism  on lit.literature_id = Organism.literature_id
                        WHERE organism_id='$org1'
                        UNION ALL
                        SELECT lit.literature_id,  lit.title1, lit.title2 
                        FROM lit
                        INNER JOIN biogeography  on lit.literature_id = biogeography.literature_id
                        WHERE organism_id='$org1'
                        UNION ALL
                        SELECT lit.literature_id,  lit.title1, lit.title2
                        FROM lit
                        INNER JOIN ecology  on lit.literature_id = ecology.literature_id
                        WHERE organism_id='$org1' group by lit.literature_id 

                        ");
    while($row = mysql_fetch_row($result1)) {
                        echo "
                        <td>$row[0]</td>
                        <td><i><b>'$row[1]',
                        '$row[2]'</i></b><br>

                        </td>
                        <td>$row[8]</td>

                                </tr>";

如何从$ result1中删除重复的id

result image

1 个答案: