以编程方式将ID分配给EditText

Question

我有一个ImageButton，当用户点击它时，EditText被添加到布局中。所以我想要的是每个EditText都有一个唯一的id。

a = 0;
imgAddText.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View v) {
       if (a <= 5) {
           layoutAddText.addView(createEditText());
           a++;
       }
    }
});

private EditText createEditText() {
    final LinearLayout.LayoutParams layoutParams = new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.WRAP_CONTENT);
    final EditText editText = new EditText(this);
        return editText;
}

Answer 1

actually all view have setId method. You can make use of it.

setId(int id)

i would strong suggest you use setTag instead. I hope reason being your setting id is using same id to get it back by findViewId(int). Same thing you can achieve by findViewWithTag(Object tag)

Answer 2

In createEditText() method try this

    EditText editText=(EditText)findViewById(R.id.edit);
    editText.setLayoutParams(layoutParams);
    editText.setId(R.id.edit);
    return editText;

Answer 3

您可以尝试将标记而不是ID设置为：

editText.setTag(UUID.randomUUID().toString());

或通过创建类似IdGenerator的类来生成唯一ID：

public class IdGenerator() {
    private static final AtomicInteger sNextGeneratedId = new AtomicInteger(1);
    public static int generateViewId() {
        for (; ; ) {
            final int result = sNextGeneratedId.get();
            int newValue = result + 1;
            if (newValue > 0x00FFFFFF) newValue = 1;
            if (sNextGeneratedId.compareAndSet(result, newValue)) {
                return result;
            }
        }
    }
}

然后做：

editText.setId(IdGenerator.generateViewId());