Question

任何人都可以帮助我使用preg_replace吗？我有一个字符串，我需要过滤掉它：

health=0.30799794

“health =”每次都在字符串中。但背后的数字是不同的。有没有办法在PHP中使用perg_replace？

Answer 1

可能你正在寻找这个：

$filter = '/health=0.30799794/';
$str = 'I am not here and my health=0.30799794';

echo $str = preg_replace ($filter, "", $str); //I am not here and my

<强>更新

只需更改过滤器：

$filter = '/health=[0-9]*.[0-9]*/'; 要么 $filter = '/health=\d*.\d*/';

Answer 2

        <?php
            $pattern    = "#(health=[0-9\.]*)#";
            $sample     = "The Student has not got the best health-status - health=0.30799794 and he is not so happy with it.";
            $result     = preg_replace($pattern, "", $sample);

            var_dump($result);
            //DUMPS: The Student has not got the best health-status -  and he is not so happy with it.

如何在php中使用preg_replace（）？

2 个答案: