Question

我想创建一个Array Strings存储“名称”;并且这些名称应该用于创建由数组中的字符串命名的新ArrayLists。

这种方式不起作用。有没有办法管理这个或者你可以解释为什么不可能？

public String combiTop [] = {"1er","2er","3er","4er","5er","6er"};

topRowValue = new ArrayList<>();
        for (int i = 0; i < combiTop.length; i++) {
            ArrayList<Integer> combiTop[i] = new ArrayList<>();
            for (int j = 0; j < 6; j++) {
                combiTop[i].add(-1);
            }
            topRowValue.add(combiTop[i]);
        }

Answer 1

在Java中，同一函数中的变量是固定类型的，因此您不能将ArrayList值分配给String数组或其内部的值。因此：

def download_attachments_in_mailbox(self):
    # Note: This function definition needs to be placed
    #       before the previous block of code that calls it.
    rv, data = self._M.search(None, "ALL")
    if rv != 'OK':
        print "No messages found!"
        return

    for num in data[0].split():
        rv, data = self._M.fetch(num, '(RFC822)')
        if rv != 'OK':
            print "ERROR getting message", num
            return

        mail = email.message_from_string(data[0][1])
        for part in mail.walk():
            if part.get_content_maintype() == 'multipart':
                # print part.as_string()
                continue
            if part.get('Content-Disposition') is None:
                # print part.as_string()
                continue
            fileName = part.get_filename()

            if bool(fileName):
                filePath = os.path.join(detach_dir, fileName)
                if not os.path.isfile(filePath):
                    print fileName
                    fp = open(filePath, 'wb')
                    fp.write(part.get_payload(decode=True))
                    fp.close()

使用字符串数组中的字符串初始化新对象

1 个答案: