Question

我有一个这样的数组：

$array = array(10,25,47,14,45,58,25,29,15,36,45,15,25,27,34);

有没有办法用键输出10个范围的新数组，告诉我使用哪个和频率值？

$result = array(
    [x0] => frequency // number of values <= x0
    [x1] => frequency // number of values > x0 and <=1
    etc..., [x2], ...., [x7], x[8]
    [x9] => frequency  // number of values >= x9
    )

Answer 1

您可以使用array_count_values()来计算值

$array = array(10,25,47,14,45,58,25,29,15,36,45,15,25,27,34);
$vals = array_count_values($array);
echo "<pre>"; print_r($vals);

这会给你

Array
(
    [10] => 1
    [25] => 3
    [47] => 1
    [14] => 1
    [45] => 2
    [58] => 1
    [29] => 1
    [15] => 2
    [36] => 1
    [27] => 1
    [34] => 1
)

Answer 2

将其用于10个相等的段

    $array = array(10,25,47,14,45,58,25,29,15,36,45,15,25,27,34);

    $step = (max($array) - min($array)) / 10;

    $result = [];
    for ($i = min($array); $i < max($array) - $step; $i += $step) {
        $res = array_filter($array, function($v) use ($i, $step) {
            return ($i <= $v) && $v < $i +$step;
        });
        $result[$i . '-' . ($i + $step)] = $res;
    }

返回：

  "10 - 14.8" => 2
  "14.8 - 19.6" => 2
  "19.6 - 24.4" => 0
  "24.4 - 29.2" => 5
  "29.2 - 34" => 0
  "34 - 38.8" => 2
  "38.8 - 43.6" => 0
  "43.6 - 48.4" => 3
  "48.4 - 53.2" => 0
  "53.2 - 58" => 0

Answer 3

我已经使用数组作为范围边界。这里有4个不规则范围的例子。然后转储已排序的数组，以便更容易查看结果是否符合您的期望。

<?php
$array  = array(10,25,47,14,45,58,25,29,15,36,45,15,25,27,34);
$bounds = array(0,10,25,50,100);
$lower  = array_shift($bounds);
$range_frequencies = array();
sort($array);
var_dump($array);
foreach($bounds as $upper) {
    $range_frequencies[$lower . '-' . $upper] = 0;
    foreach($array as $k => $v) {
        if($v > $lower && $v <= $upper) {
            $range_frequencies[$lower . '-' . $upper]++;
            unset($array[$k]);
        }
    }
    $lower = $upper;
}
var_dump($range_frequencies);

输出：

array (size=15)
  0 => int 10
  1 => int 14
  2 => int 15
  3 => int 15
  4 => int 25
  5 => int 25
  6 => int 25
  7 => int 27
  8 => int 29
  9 => int 34
  10 => int 36
  11 => int 45
  12 => int 45
  13 => int 47
  14 => int 58
array (size=4)
  '0-10' => int 1
  '10-25' => int 6
  '25-50' => int 7
  '50-100' => int 1

Answer 4

根据Manjeet Barnala的回答：

$array = array(10,25,47,14,45,58,25,29,15,36,45,15,25,27,34);
$vals = array_count_values($array);
arsort($vals);
$vals = array_slice($vals,0,10,true);

var_dump($vals);

PHP - 如何计算范围有限的数组的所有值？

4 个答案: