我有100个文件名如下文件:
asdf_01, asdf_02, asdf_03, asdf_04, asdf_05, etc.
dfgh_01, dfgh_02, dfgh_03, dfgh_04, dfgh_05, etc.
我想粘贴具有相同结尾的文件,如下所示:
paste asdf_01 dfgh_01 > pasted_01
如何对所有文件应用此命令?
答案 0 :(得分:0)
for i in {00..99}; do
paste "asdf_$i" "dfgh_$i" > "pasted_$i"
done
答案 1 :(得分:-1)
基本上你可以使用以下的glob表达式:
paste *_01 > pasted_01
要迭代所有可能的值,您需要一个循环:
for suffix in {01..99} ; do
# Check if there are exactly two files with that suffix
if [ $(($(find -name "*${suffix}" -printf . | wc -c))) -eq 2 ] ; then
paste *_"${suffix}" > pasted_"${suffix}"
fi
done