我正在使用fullcalendar和google calendar api,我将我的活动输出,并希望将它们作为json传递给我的fullcalendar,因为fullcalendar事件接受它作为数据源并自动将它们呈现到日历中。
我有我的html文件,其中包含许多资源和一个创建日历的jQuery脚本:
<html>
<head>
<link rel='stylesheet' href='fullcalendar/fullcalendar.css' />
<script src='fullcalendar/lib/jquery.min.js'></script>
<script src='fullcalendar/lib/moment.min.js'></script>
<script src='fullcalendar/fullcalendar.js'></script>
<script type='text/javascript' src='fullcalendar/gcal.js'></script>
<script src='fullcalendar/lang/da.js'></script>
<script type='text/javascript'>
$(document).ready(function() {
$('#calendar').fullCalendar({
defaultView: 'agendaWeek',
weekends: false,
lang: 'da',
header: false,
allDaySlot: false,
allDayText: '',
height: 695,
minTime: '06:00:00',
maxTime: '20:00:00',
events: 'calendarData.js'
});
});
</script>
</head>
<body>
<div id="calendar"></div>
</body>
</html>
注意事件:将json对象放入。我有一个json文件,其中包含与我正在尝试创建的相同的硬编码json对象,并且工作正常。但是在以下javascript文件中出现了错误/错误。
calendarData.js
var CLIENT_ID = 'id';
var SCOPES = ["https://www.googleapis.com/auth/calendar.readonly"];
/**
* Check if current user has authorized this application.
*/
function checkAuth() {
gapi.auth.authorize(
{
'client_id': CLIENT_ID,
'scope': SCOPES.join(' '),
'immediate': true
}, handleAuthResult);
}
/**
* Handle response from authorization server.
*
* @param {Object} authResult Authorization result.
*/
function handleAuthResult(authResult) {
var authorizeDiv = document.getElementById('authorize-div');
if (authResult && !authResult.error) {
// Hide auth UI, then load client library.
authorizeDiv.style.display = 'none';
loadCalendarApi();
} else {
// Show auth UI, allowing the user to initiate authorization by
// clicking authorize button.
authorizeDiv.style.display = 'inline';
}
}
/**
* Initiate auth flow in response to user clicking authorize button.
*
* @param {Event} event Button click event.
*/
function handleAuthClick(event) {
gapi.auth.authorize(
{client_id: CLIENT_ID, scope: SCOPES, immediate: false},
handleAuthResult);
return false;
}
/**
* Load Google Calendar client library. List upcoming events
* once client library is loaded.
*/
function loadCalendarApi() {
gapi.client.load('calendar', 'v3', listUpcomingEvents);
}
/**
* Print the summary and start datetime/date of the next ten events in
* the authorized user's calendar. If no events are found an
* appropriate message is printed.
*/
function listUpcomingEvents() {
var request = gapi.client.calendar.events.list({
'calendarId': 'primary',
'timeMin': (new Date()).toISOString(),
'showDeleted': false,
'singleEvents': true,
'maxResults': 10,
'orderBy': 'startTime'
});
var json = {};
request.execute(function(resp) {
var events = resp.items;
json.json = [];
if (events.length > 0) {
for (i = 0; i < events.length; i++) {
var event = events[i];
var when = event.start.dateTime;
if (!when) {
when = event.start.date;
}
json.json.push({id : i+1, title : event.summary, start : event.start.dateTime, end : event.end.dateTime, desc : event.description});
}
}
});
return json;
}
正如您可能会看到,除了最后的json之外,这非常接近api日历javascript快速入门。我希望脚本将json对象返回到fullcalendar,但这不起作用,所以如果可能的话我怎么能改变它呢?
当我对对象进行字符串化并提醒时,我可以看到创建的对象与之前提到的json文件相同。
编辑: 我正在谈论的json文件以及可以使用的数据如下所示:
[{"id":"1","title":"Test 1","start":"2016-05-26","end":"2016-05-26T16:30:00","allDay":false},{"id":"2","title":"Test 2","start":"2016-05-26","end":"2016-05-26T17:00:00","allDay":false},{"id":"3","title":"Test 3","start":"2016-05-27T08:00:00","end":"","allDay":false}]
当我对字符串进行字符串化并提醒它时,它看起来像这样:
var myObject = JSON.stringify(json);
alert(myObject);
{"json":[{"id":1,"title":"ghhgfgh","start":"2016-05-26T14:30:00+02:00","end":"2016-05-26T15:30:00+02:00"}]}
答案 0 :(得分:1)
你的问题在这里:
$(document).ready(function () {
$('#calendar').fullCalendar({
defaultView: 'agendaWeek',
weekends: false,
lang: 'da',
header: false,
allDaySlot: false,
allDayText: '',
height: 695,
minTime: '06:00:00',
maxTime: '20:00:00',
events: 'calendarData.js'
});
});
&#34;事件&#34;不能将javascript文件作为输入或直接json字符串。您可以为其指定array of events,URL或function。
我猜你打算提供&#34;事件&#34;使用 listUpcomingEvents()函数的结果。
你可以这样做(只需确保你在HTML文件中添加 calendarData.js 作为脚本src):
$(document).ready(function () {
$('#calendar').fullCalendar({
defaultView: 'agendaWeek',
weekends: false,
lang: 'da',
header: false,
allDaySlot: false,
allDayText: '',
height: 695,
minTime: '06:00:00',
maxTime: '20:00:00',
events: function(start, end, timezone, callback){
callback(listUpcomingEvents());
},
});
});
答案 1 :(得分:0)
要在您要使用的JS / JSON对象之间进行交互:
JSON.stringify()
JSON.parse()
例如:JS&gt; JSON&gt; JS
var x = {
y: 'hello',
z: 1
};
console.log(JSON.parse(JSON.stringify(x)));
答案 2 :(得分:0)
将其转换为JSON对象,如下所示:
var Jobj = JSON.parse(your_string_data);