Question

此时用户使用注册表格进行注册如果电子邮件已经存在于数据库中，则会显示“已存在的电子邮件”消息，其他用户可以完成注册。但不能显示消息我错了什么？

我的控制器

public function emailCheck()
{
    $this->autoRender = false;
    $this->viewBuilder()->layout('false');
    if ($this->request->is(['post'])) {
         $search =$this->request->data('email');                                                  
         $query = $this->Users->find('list', [
                              'conditions' => ['Users.email LIKE '=>'%' .$search. '%'],
                              'limit' => 1
                              ])->all();
         foreach ($query as $key) {
             if($key!=null){
                echo "This email has been taken!!";
             }else
             echo "Email avilable.";
         }
    } 
}

我的Ajax

<script>
$('document').ready(function(){
    $('input[name="email"]').change(function(){
        var email = $(this).val();
        $.ajax({
                  method:'POST',
                  url:'<?php echo Router::url(['controller' => 'Users', 'action' => 'emailCheck']); ?>',
                  data:{search:email},
                  success: function(data)
                  {
                    alert(data);
                  }
        });
    })
})

Answer 1

如果我理解正确：您声明var ex = OwinRequestScopeContext.Current.Items["error"] as Exception;，但是以find('list')结束查询，返回一个对象数组（即使您将其限制为1）。因此，all()永远不会只是$key。但是，您可以尝试使用给定的电子邮件找到第一条记录：

null

注意：我还从您的查询中删除了$query = $this->Users->find('list', [ 'conditions' => ['Users.email LIKE'=> $search], ])->first(); if (is_null($query)) { // the email is still available } else { // the email is already in use }通配符：将它们留在那里会导致误报，例如：当有人订阅%时，123johndoe@gmail.com会收到他的电子邮件已被使用的消息}

Answer 2

最后我得到了解决方案。解决方案是我的控制器

    public function emailCheck()
{
    $this->autoRender = false;
    $this->viewBuilder()->layout('false');
    if ($this->request->is(['post'])) {
        $email =$this->request->data('email');                                                 
        $query = $this->Users->find()
            ->where(['Users.email '=>$email])->count();
        if($query) {
             echo 1;
        }
    }
}

我的Ajax

<script>
$('document').ready(function(){
    $('#email').keyup(function(){
        var email = $(this).val();
        $.ajax({
                  method:'POST',
                  url:'<?php echo Router::url(['controller' => 'Users', 'action' => 'emailCheck']); ?>',
                  dataType: "text",
                  data:{email:email},
                  success: function(data)
                  {
                      if(data){
                          $( ".result" ).html('<span style="color:red">Someone already has that username. Try another?</span>');
                      }else{
                         $( ".result" ).html('<span style="color:green">The email is still available!!</span>');
                      }

                  }
        });
    })

}）

这些脚本完全用于检查重复的email.testing由我

cakephp 3检查重复的电子邮件并发送消息，电子邮件已退出

2 个答案: