Question

我有一个在我的系统上成功运行的maven项目。此maven项目将任何Web URL作为输入。现在，我想在点击我的chrome扩展时调用这个Maven项目。我的chrome扩展程序能够获取网站的URL。

那我怎么能这样做？在搜索谷歌和许多其他资源时，我发现我必须制作一个可以听取客户端行为的宁静网络服务。

但是我还不清楚怎么做呢？甚至最初的步骤对我来说都不清楚？

任何想法对我都有帮助！

我对REST端点/邮递员一无所知，这只是我收集的信息。

P.S如果我描述的情景不清楚，请发表评论，我会尝试添加更多细节。

编辑1

这是JS的源代码

document.addEventListener('DOMContentLoaded', function () {

      chrome.tabs.query({ currentWindow: true, active: true }, function (tabs) {
      alert(tabs[0].url)
      var req = new XMLHttpRequest();
      req.open("POST", "http://localhost:8080/SalesRESTservice/apicall/restcall2", true);
      req.onload = onResponseReceived;
      var par = 99.99;
      req.send(par);

        function onResponseReceived() {
            alert("It worked.");
        }
      // document.getElementById('Current_url').value = tabs[0].url;
      //console.log(tabs[0].url, tabs[0].title, tabs[0].incognito, tabs, this.bookmark_title);
    });
  });

这是我的JAVA端点代码

import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.core.Response;
import org.json.JSONException;
import org.json.JSONObject;

@Path("/restcall2")
public class restcall2 {

      @POST
      @Produces("application/json")
      public Response convertFtoC(Double param) throws JSONException {

        JSONObject jsonObject = new JSONObject();
        Double fahrenheit = param;
        Double celsius;
        celsius = (fahrenheit - 32)*5/9; 
        jsonObject.put("F Value", fahrenheit); 
        jsonObject.put("C Value", celsius);

        String result = "@Produces(\"application/json\") Output: \n\nF to C Converter Output: \n\n" + jsonObject;
        return Response.status(200).entity(result).build();
      }

}

我尝试将fahrenheit的值发送到java func。但是它会出错？

控制台错误

INFO: Server startup in 1052 ms
May 27, 2016 1:54:17 PM com.sun.jersey.spi.container.ContainerRequest getEntity
SEVERE: A message body reader for Java class java.lang.Double, and Java type class java.lang.Double, and MIME media type application/octet-stream was not found.
The registered message body readers compatible with the MIME media type are:
application/octet-stream ->
  com.sun.jersey.core.impl.provider.entity.ByteArrayProvider
  com.sun.jersey.core.impl.provider.entity.FileProvider
  com.sun.jersey.core.impl.provider.entity.InputStreamProvider
  com.sun.jersey.core.impl.provider.entity.DataSourceProvider
  com.sun.jersey.core.impl.provider.entity.RenderedImageProvider
*/* ->
  com.sun.jersey.core.impl.provider.entity.FormProvider
  com.sun.jersey.core.impl.provider.entity.StringProvider
  com.sun.jersey.core.impl.provider.entity.ByteArrayProvider
  com.sun.jersey.core.impl.provider.entity.FileProvider
  com.sun.jersey.core.impl.provider.entity.InputStreamProvider
  com.sun.jersey.core.impl.provider.entity.DataSourceProvider
  com.sun.jersey.core.impl.provider.entity.XMLJAXBElementProvider$General
  com.sun.jersey.core.impl.provider.entity.ReaderProvider
  com.sun.jersey.core.impl.provider.entity.DocumentProvider
  com.sun.jersey.core.impl.provider.entity.SourceProvider$StreamSourceReader
  com.sun.jersey.core.impl.provider.entity.SourceProvider$SAXSourceReader
  com.sun.jersey.core.impl.provider.entity.SourceProvider$DOMSourceReader
  com.sun.jersey.json.impl.provider.entity.JSONJAXBElementProvider$General
  com.sun.jersey.core.impl.provider.entity.XMLRootElementProvider$General
  com.sun.jersey.core.impl.provider.entity.XMLListElementProvider$General
  com.sun.jersey.core.impl.provider.entity.XMLRootObjectProvider$General
  com.sun.jersey.core.impl.provider.entity.EntityHolderReader
  com.sun.jersey.json.impl.provider.entity.JSONRootElementProvider$General
  com.sun.jersey.json.impl.provider.entity.JSONListElementProvider$General

May 27, 2016 1:54:19 PM com.sun.jersey.spi.container.ContainerRequest getEntity
SEVERE: A message body reader for Java class java.lang.Double, and Java type class java.lang.Double, and MIME media type application/octet-stream was not found.
The registered message body readers compatible with the MIME media type are:
application/octet-stream ->
  com.sun.jersey.core.impl.provider.entity.ByteArrayProvider
  com.sun.jersey.core.impl.provider.entity.FileProvider
  com.sun.jersey.core.impl.provider.entity.InputStreamProvider
  com.sun.jersey.core.impl.provider.entity.DataSourceProvider
  com.sun.jersey.core.impl.provider.entity.RenderedImageProvider
*/* ->
  com.sun.jersey.core.impl.provider.entity.FormProvider
  com.sun.jersey.core.impl.provider.entity.StringProvider
  com.sun.jersey.core.impl.provider.entity.ByteArrayProvider
  com.sun.jersey.core.impl.provider.entity.FileProvider
  com.sun.jersey.core.impl.provider.entity.InputStreamProvider
  com.sun.jersey.core.impl.provider.entity.DataSourceProvider
  com.sun.jersey.core.impl.provider.entity.XMLJAXBElementProvider$General
  com.sun.jersey.core.impl.provider.entity.ReaderProvider
  com.sun.jersey.core.impl.provider.entity.DocumentProvider
  com.sun.jersey.core.impl.provider.entity.SourceProvider$StreamSourceReader
  com.sun.jersey.core.impl.provider.entity.SourceProvider$SAXSourceReader
  com.sun.jersey.core.impl.provider.entity.SourceProvider$DOMSourceReader
  com.sun.jersey.json.impl.provider.entity.JSONJAXBElementProvider$General
  com.sun.jersey.core.impl.provider.entity.XMLRootElementProvider$General
  com.sun.jersey.core.impl.provider.entity.XMLListElementProvider$General
  com.sun.jersey.core.impl.provider.entity.XMLRootObjectProvider$General
  com.sun.jersey.core.impl.provider.entity.EntityHolderReader
  com.sun.jersey.json.impl.provider.entity.JSONRootElementProvider$General
  com.sun.jersey.json.impl.provider.entity.JSONListElementProvider$General

Answer 1

从https://jersey.java.net/开始 Jersey RESTful Web Services框架是开源的。你会从那里得到一个简短的想法。

此外，您可以在此处获取基本的平针织网页应用程序 https://github.com/Vijendra07Kulhade/jersey-quickstart

只需克隆它并运行maven install。

要运行maven项目，请在pom.xml中添加以下插件

<plugin>
    <groupId>org.apache.tomcat.maven</groupId>
    <artifactId>tomcat7-maven-plugin</artifactId>
    <version>2.2</version>
  </plugin>

您可以从上面的github repo中获取参考。

运行命令mvn tomcat7:run 它将在tomcat中运行您的项目。它还将告诉它部署的上下文。类似下面的东西。你可以从邮递员那里得到这个。

localhost:8080/someContext/

Answer 2

如果您编写了一个REST控制器，它应该启动并监听传入的请求。您需要将这些端点作为请求URL提供，并在您的扩展中获取信息。您可以直接使用浏览器或使用POSTMAN等扩展来检查和测试REST端点。您可以从chrome扩展程序向REST端点创建XMLHttpRequest。

用于调用REST API端点的JS示例：

var req = new XMLHttpRequest();
req.open("GET", "http://api.myrestapi.com/services/rest/getEmployee", true);
req.onload = onResponseReceived;
req.send(null);

function onResponseReceived() {
    console.log("It worked.");
}

如果你需要使用POST方法发送参数，试试这个，

var http = new XMLHttpRequest();
var someValue = "99.99";
var url = "http://localhost:8080/SalesRESTservice/apicall/restcall2/"+param;
var params = JSON.stringify({ param: someValue });
http.open("POST", url, true);

http.setRequestHeader("Content-type", "application/json; charset=utf-8");
http.setRequestHeader("Content-length", params.length);
http.setRequestHeader("Connection", "close");

http.onreadystatechange = function() {
    if(http.readyState == 4 && http.status == 200) {
        alert(http.responseText);
        //or do some callback
    }
}
http.send(params);

调用maven项目时的困惑

2 个答案: