Question

我试图测试以下组件。

MyComponent -

export class MyComponent {
  radioItems: any;
  selectedItem: number = 0;
  name: string;

  constructor(private _reset: ForgotPwdService, private _router: Router) {
    if (!_reset.storedMails || !_reset.fullName) {
      _router.root.navigate(['ParentRoutePath']); // Using parent route, _router.parent.navigate() doesn't work for test either
      return;
    }
    this.name = _reset.fullName;
    this.radioItems = _reset.storedMails;
  }

  getValue(event) {
    this.selectedItem = event;
  }

  onClick() {
    this._reset.mail = this.radioItems[this.selectedItem].title;
    this._router.navigate(['RoutePath']); //Using route
  }
}

在测试中，在beforeEach()方法中，我提供了以下路由组件 - provide(ROUTER_PRIMARY_COMPONENT, {useValue: ComponentWithChildRoute})。但是，当我尝试运行测试时，我在测试中遇到以下错误，尝试验证构造函数中的代码 - Component "ComponentWithChildRoute" has no route named "ParentRoutePath".如果我尝试提供provide(ROUTER_PRIMARY_COMPONENT, {useValue: RootRouteComponent})，我和＃39;在运行Component "RootRouteComponent" has no route named "RoutePath".方法的测试中出现onClick()错误。有办法解决吗？也许我可以在所需的测试中提供一个路由组件，而不是在beforeEach（）中？

两项测试的代码 -

  it('should redirect to login when storedMails or fullName are empty',
    fakeAsync(inject([ForgotPwdService, Location, Router],
      (forgot: ForgotPwdService, location: Location, route: Router) => {
        forgot.storedMails = '';
        let mail = new NameSent(forgot, route);

        tick();

        expect(location.path()).toContain('/login');
      })
    )
  );

  it('should direct to selected item when specified',
    fakeAsync(inject([NameSent, Location], (name: NameSent, location: Location) => {
      name.onClick();

      tick();

      expect(location.path()).toContain('/mail-sent');
    }))
  );

更新

我设法通过以下方式重写这些测试来解决这个问题 -

  it('should direct to selected item when specified',
    fakeAsync(inject([NameSent, Router], (name: NameSent, router: Router) => {
      spyOn(router, 'navigate');
      name.onClick();

      expect(router.navigate).toHaveBeenCalledWith(['MailSent']);
    }))
  );

但是，如果有可能以某种方式注入多个路径组件，我仍然感兴趣吗？

使用不同路由组件的单元测试组件

更新

0 个答案: