Question

是否可以将point对象作为参数传递给run函数？以下代码会导致TypeError: signal() only accepts 0 arguments, 2 given!

import PySide.QtCore as QtCore

def run(arg = None, *args, **kwargs):
    print 'run:', arg, args, kwargs

class Emitter(QtCore.QObject):
    signal = QtCore.Signal()

emitter = Emitter()
emitter.signal.connect(run)

point = QtCore.QPoint()
emitter.signal.emit(point)

Answer 1

您必须指定要发送的对象的类型。例如，传递带信号的int。

def Emitter(QtCore.QObject):
    signal = QtCore.Signal(int)

我建议阅读更多有关此内容的文档。例如，https://wiki.qt.io/Signals_and_Slots_in_PySide。

Answer 2

方法1.0：在声明object时指定signal = QtCore.Signal(object)作为类型：

import PySide.QtCore as QtCore

def run(arg = None, *args, **kwargs):
    print 'run:', arg, args, kwargs

class Emitter(QtCore.QObject):
    signal = QtCore.Signal(object) 

emitter = Emitter()
emitter.signal.connect(run)

point = QtCore.QPoint()

emitter.signal.emit(point)

方法1.1：使用相同的方法传递多个参数：

import PySide.QtCore as QtCore

def run(arg = None, *args, **kwargs):
    print 'run:', arg, args, kwargs

class Emitter(QtCore.QObject):
    signal = QtCore.Signal(object, object, str, int, dict, list, tuple) 

emitter = Emitter()
emitter.signal.connect(run)

point = QtCore.QPoint()
point2 = QtCore.QPoint()
emitter.signal.emit(point, point2, 'foo', 10, {1:'one'}, [1,2], (1, 2))

方法2：

在声明tuple时指定类型signal：

 signal = QtCore.Signal(tuple)

所有传递的参数后面都应加一个逗号：...emit(point,)

import PySide.QtCore as QtCore

def run(arg = None, *args, **kwargs):
    print 'run:', arg, args, kwargs

class Emitter(QtCore.QObject):
    signal = QtCore.Signal(tuple) 

emitter = Emitter()
emitter.signal.connect(run)

point = QtCore.QPoint()

emitter.signal.emit(point,)

如何通过信号传递对象参数

2 个答案: