Question

我对PHP数组有一个非常蹩脚的问题，我试图获取[extras] []的所有值，在这种情况下它们是1,2,3,4，这里是print_r（$ array）的输出：

   Array
(
    [0] => Array
        (
            [name] => form[pickupDate][day]
            [value] => 1
        )

    [1] => Array
        (
            [name] => form[pickupDate][month]
            [value] => 10
        )

    [2] => Array
        (
            [name] => form[pickupTime][hour]
            [value] => 0
        )

    [3] => Array
        (
            [name] => form[returnDate][day]
            [value] => 1
        )

    [4] => Array
        (
            [name] => form[returnDate][month]
            [value] => 1
        )

    [5] => Array
        (
            [name] => form[returnTime][hour]
            [value] => 0
        )

    [6] => Array
        (
            [name] => form[car]
            [value] => 1
        )

    [7] => Array
        (
            [name] => form[pickupAddress]
            [value] => 
        )

    [8] => Array
        (
            [name] => form[agency]
            [value] => 1
        )

    [9] => Array
        (
            [name] => form[extras][]
            [value] => 1
        )

    [10] => Array
        (
            [name] => form[extras][]
            [value] => 2
        )

    [11] => Array
        (
            [name] => form[extras][]
            [value] => 3
        )

    [12] => Array
        (
            [name] => form[extras][]
            [value] => 4
        )

    [13] => Array
        (
            [name] => form[specialPrice]
            [value] => 
        )

)

你可以使用这个JSON字符串来播放我的数据，之后将它转换为PHP数组，如下所示：

$request = '[{"name":"form[pickupDate][day]","value":"1"},{"name":"form[pickupDate][month]","value":"8"},{"name":"form[pickupTime][hour]","value":"0"},{"name":"form[returnDate][day]","value":"1"},{"name":"form[returnDate][month]","value":"1"},{"name":"form[returnTime][hour]","value":"0"},{"name":"form[pickupAddress]","value":""},{"name":"form[agency]","value":"1"},{"name":"form[extras][]","value":"1"},{"name":"form[extras][]","value":"2"},{"name":"form[extras][]","value":"3"},{"name":"form[extras][]","value":"4"},{"name":"form[specialPrice]","value":""}]';
$array = json_decode($request,true);

我已经尝试过这个，但它产生的字符串（1）＆＃34; 4＆＃34;：

$result = array_column($array, null, 'name')['form[extras][]']['value'];
var_dump($result);

Answer 1

你有一个多维数组，这是一个由多个数组组成的数组。

monitor.sh &

这就是为什么你必须遍历每个元素，例如使用这个函数（你已经在PHP中定义了一个＆gt; 5.5.0）：

array->[0]-[1]-[2]...  
        |   |
        |   [name]-[value]
        | 
array-> [name]-[value]

编辑：用于根据名称获取特定数组子集的值：

function array_column($array, $value)
{
    $result = array();
    foreach($array as $element)
    {
        $result[] = $element[$value];
    }
    return $result[];
}

试图在PHP中获取关联数组的值

1 个答案: