Question

我正在尝试编写此SQL语句以从另一个表中选择日期范围并将其用于过滤结果。

我把SQL语句放在一起，但不管怎么说它不起作用。

感谢您的帮助

SELECT 
    a.jednota,datum, 
    SUM(CASE WHEN a.co='prijem' THEN a.kusy ELSE NULL END) as prijem_ks, 
    SUM(CASE WHEN a.co='predaj' THEN a.kusy ELSE NULL END) as predaj_ks 
FROM 
    jednotypredaj as a

SELECT 
    b.id, b.fromd, b.tod 
FROM
    datadocasne as b 
WHERE 
    (a.tovar LIKE 'kalan' AND datum BETWEEN 'b.fromd' AND 'b.tod')
GROUP BY 
    a.jednota
ORDER BY
    predaj_ks DESC

表datadocasne：

id      fromt       tod
---------------------------------
1       12.4.2016     22.5.2016

表jednotypredaj：

co       datum        jednota   tovar      kusy
------------------------------------------------
predaj   12.5.2016   TR003      kalan       5
predaj   25.5.2016   TR278      aechmea     6
predaj   11.4.2016   TR202      phalenopsis 8

结果应如下所示

co       datum       jednota   tovar   kusy
predaj   12.5.2016   TR003     kalan   5

Answer 1

只需在JOIN子句中添加条件。

SELECT
    J.co,
    J.datum,
    J.jednota,
    J.tovar,
    J.kusy
FROM
    datadocasne D
INNER JOIN jednotypredaj J ON J.datum BETWEEN D.fromd AND D.tod

Answer 2

您可能需要做这样的事情......

SELECT a.jednota,b.id,b.fromd,b.tod,
      SUM(CASE WHEN a.co='prijem' THEN a.kusy ELSE NULL END) as prijem_ks, 
      SUM(CASE WHEN a.co='predaj' THEN a.kusy ELSE NULL END) as predaj_ks 
      FROM jednotypredaj a
      join datadocasne b on a.datum between b.fromd and b.tod
 WHERE a.tovar LIKE 'kalan'
GROUP BY a.jednota,b.id,b.fromd,b.tod,
      SUM(CASE WHEN a.co='prijem' THEN a.kusy ELSE NULL END), 
      SUM(CASE WHEN a.co='predaj' THEN a.kusy ELSE NULL END)
ORDER by predaj_ks DESC

我想编写一个SQL语句来从另一个表

2 个答案: