我的php脚本以下面显示的格式向我的swift iOS应用程序发送JSON响应。使用以下代码将其解析为NSArray
:
let jsonArray = try NSJSONSerialization.JSONObjectWithData(data_fixed!, options:[])
我在swift代码中创建了以下对象:
class Friend : NSObject {
var name: String?
var id: String?
var profile_pic : String?
}
class Message : NSObject {
var id: String?
var text: String?
var date: NSDate?
var sender: Friend?
}
class Chat : NSObject {
var id : String?
var chat_partner : Friend?
var chat_messages : [Message]?
}
我现在想要做的是遍历下面的NSArray
,并将数据提取到我的对象的实例中,所以简单来说,通过下面的例子,我想创建两个带有id&#的聊天对象39; s 1和2,以及所有适当的变量。我不确定如何在swift中正确执行这样的循环。
JSON响应:
Array: (
{
chatId = 1;
message = {
1 = {
chatId = 1;
"message_id" = 24242241;
sender = 1233;
text = "hello i am";
timestamp = "2016-05-24 17:13:08";
};
2 = {
chatId = 1;
"message_id" = 421421;
sender = 1233;
text = great;
timestamp = "2016-05-24 17:15:08";
};
};
"user1_id" = 1233;
"user1_name" = David;
"user1_profile_pic" = "http://graph.facebsddsaadsadsook.com/1233/picture?type=large";
"user2_id" = 8543211123;
"user2_name" = 0;
"user2_profile_pic" = "<null>";
},
{
chatId = 2;
"user1_id" = 23413524635;
"user1_name" = 0;
"user1_profile_pic" = "<null>";
"user2_id" = 1233;
"user2_name" = David;
"user2_profile_pic" = "http://graph.facebsdadsook.com/1233/picture?type=large";
}
)
更新:代码尝试
var count_chats = 0;
for anItem in jsonArray as! [Dictionary<String, AnyObject>] {
let curr_chat = Chat()
if let chatId = anItem["chatId"] as? String {
curr_chat.id = chatId
}
let friend = Friend()
let user1id = anItem["user1_id"] as! String
let user2id = anItem["user2_id"] as! String
if (user1id == userID) {
if let user2id = anItem["user2_id"] as? String {
friend.id = user2id
}
if let user2name = anItem["user2_name"] as? String {
friend.name = user2name
}
if let user2profilepic = anItem["user2_profile_pic"] as? String {
friend.profile_pic = user2profilepic
}
}
else if (user2id == userID){
if let user1id = anItem["user1_id"] as? String {
friend.id = user1id
}
if let user1name = anItem["user1_name"] as? String {
friend.name = user1name
}
if let user1profilepic = anItem["user1_profile_pic"] as? String {
friend.profile_pic = user1profilepic
}
}
print("passed")
curr_chat.chat_partner = friend
var chat_messages : [Message]? = nil
var count_messages = 0;
if let dataArray = anItem["message"] as? NSArray {
for onemessage in dataArray as! [Dictionary<String, AnyObject>] {
let curr_message = Message()
if let messageid = onemessage["message_id"] as? String {
curr_message.id = messageid
}
if let messagedate = onemessage["timestamp"] as? NSDate {
curr_message.date = messagedate
}
if let messagesender = onemessage["sender"] as? String {
curr_message.sender = messagesender
}
if let messagetext = onemessage["text"] as? String {
curr_message.text = messagetext
}
chat_messages![count_messages] = curr_message
count_messages = count_messages + 1
}
}
curr_chat.chat_messages = chat_messages
self.user_chats![count_chats] = curr_chat
count_chats = count_chats + 1
答案 0 :(得分:1)
不是答案,但这可能会对您有所帮助,在撰写此类内容时,您应该检查您的财产是否为零:curr_message.id = onemessage["chatId"] as! String
。
你能做什么:
if let chatId = onemessage["chatId"] as? String {
curr_message.id = chatId
}
或者如果您希望它更简单,您可以使用Swifty JSON并写下这样的内容:
curr_message.id = onemessage["chatId"].stringValue
希望这可以帮到你!
答案 1 :(得分:0)
我真的不知道这是否真的可以帮助某人,但是我已经被这三天所困扰。我终于看到了这个问题,从字面上看,这个问题对我来说是答案,感谢@Alk。简而言之,我正在处理这种类型的数据(NSArray):
[<__NSArrayM 0x6000000556e0>(
{
author = Julioenred;
id = 1;
text = "hello world";
},
{
author = Pepe;
text = "Saludos!!";
}
)
]
我需要的数据是每个索引的作者和文本,因此我能够做到这一点:
for i in data.first as! [Dictionary<String, AnyObject>] {
let message = Message(message: "", user: "")
if let author = i["author"] as? String {
message.author = author
}
if let text = i["text"] as? String {
message.text = text
}
}
基本上,我在字典中搜索要查找的键,如果有人问,这是对象Message:
import Foundation
class Message: Mappable {
var author: String? = ""
var text: String? = ""
init(message: String, user: String) {
self.author = user
self.text = message
}
}