简单的春天<记住我> ...请帮助</remember-me>

时间：2010-09-19 02:51:29

标签： spring-security remember-me

我想要的只是一个简单的记住我。我看了http://static.springsource.org/spring-security/site/docs/3.0.x/reference/remember-me.html

到目前为止我做了什么：

  1. 创建了我自己的UserDetailsService以使用Hibernate / JPA。 我的impl。不考虑任何记住我的东西
  2. 通过appContext <security:remember-me key="89dqj219dn910lsAc12" user-service-ref="jpaUserDetailsService" token-validity-seconds="864000"/>
    3. 考虑配置
  3. 选中，确认Cookie SPRING_SECURITY_REMEMBER_ME_COOKIE已设置
  4. 登录到安全网站并运行

  5. 当我重新启动浏览器时，我一直收到错误：

    org.springframework.security.access.AccessDeniedException：访问被拒绝 身份验证对象为String：org.springframework.security.authentication.RememberMeAuthenticationToken@9ab72a70：Principal：de.myapp.businessobjects.AppUser@61f68b18：Username：myad;密码保护];启用：true; AccountNonExpired：true; credentialsNonExpired：true; AccountNonLocked：true;个人信息：65537; ;证书：[保护];认证：真实;详细信息：org.springframework.security.web.authentication.WebAuthenticationDetails@957e：RemoteIpAddress：127.0.0.1; SessionId：null;授权机构：ROLE_ADMIN，ROLE_USER

    6. 这是我的secContext.xml：

    <?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:security="http://www.springframework.org/schema/security"
       xsi:schemaLocation="
           http://www.springframework.org/schema/beans
           http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
           http://www.springframework.org/schema/security
           http://www.springframework.org/schema/security/spring-security-3.0.xsd">

    <security:global-method-security pre-post-annotations="enabled">
    </security:global-method-security>

    <security:http use-expressions="true" access-denied-page="/accessDenied">
        <security:form-login
                login-page="/login"
                login-processing-url="/loginProcess"
                default-target-url="/intro"
                authentication-failure-url="/login?login_error=1"
                />
        <security:logout
                logout-url="/logout"
                logout-success-url="/logoutSuccess"/>

        <security:intercept-url pattern="/**" access="permitAll"/>
        <security:intercept-url pattern="/login" access="permitAll"/>
        <security:intercept-url pattern="/styles/**" access="permitAll"/>
        <security:intercept-url pattern="/scripts/**" access="permitAll"/>
        <security:remember-me key="89dqj219dn910lsAc12" user-service-ref="jpaUserDetailsService"
                              token-validity-seconds="864000"/>
    </security:http>

    <security:authentication-manager alias="authenticationManager">
        <security:authentication-provider user-service-ref="jpaUserDetailsService">
            <security:password-encoder hash="sha">
            </security:password-encoder>
        </security:authentication-provider>
    </security:authentication-manager>

    <bean id="rememberMeFilter" class=
            "org.springframework.security.web.authentication.rememberme.RememberMeAuthenticationFilter">
        <property name="rememberMeServices" ref="rememberMeServices"/>
        <property name="authenticationManager" ref="authenticationManager"/>
    </bean>

    <bean id="rememberMeServices" class=
            "org.springframework.security.web.authentication.rememberme.TokenBasedRememberMeServices">
        <property name="userDetailsService" ref="jpaUserDetailsService"/>
        <property name="key" value="89dqj219dn910lsAc12"/>
    </bean>

    <bean id="rememberMeAuthenticationProvider" class=
            "org.springframework.security.authentication.RememberMeAuthenticationProvider">
        <property name="key" value="89dqj219dn910lsAc12"/>
    </bean>
</beans>

    最后是一些调试跟踪

    03:45:14.598 [7225609@qtp-10131947-7] DEBUG o.s.w.b.a.s.HandlerMethodInvoker - Invoking request handler method: public java.lang.String de.myapp.controller.bstController.showbstpage(java.lang.String,javax.servlet.http.HttpServletResponse)
03:45:14.598 [7225609@qtp-10131947-7] DEBUG o.s.s.a.i.a.MethodSecurityInterceptor - Secure object: ReflectiveMethodInvocation: public java.lang.String de.myapp.controller.bstController.showbstpage(java.lang.String,javax.servlet.http.HttpServletResponse); target is of class [de.myapp.controller.bstController]; Attributes: [[authorize: 'isFullyAuthenticated() and #username == principal.username', filter: 'null', filterTarget: 'null']]
03:45:14.598 [7225609@qtp-10131947-7] DEBUG o.s.s.a.i.a.MethodSecurityInterceptor - Previously Authenticated: org.springframework.security.authentication.RememberMeAuthenticationToken@9ab72a70: Principal: de.myapp.businessobjects.AppUser@61f68b18: Username: myad; Password: [PROTECTED]; Enabled: true; AccountNonExpired: true; credentialsNonExpired: true; AccountNonLocked: true; PersonalInformation: 65537; ; Credentials: [PROTECTED]; Authenticated: true; Details: org.springframework.security.web.authentication.WebAuthenticationDetails@957e: RemoteIpAddress: 127.0.0.1; SessionId: null; Granted Authorities: ROLE_ADMIN, ROLE_USER
03:45:14.599 [7225609@qtp-10131947-7] DEBUG o.s.c.c.s.GenericConversionService - Converting value false of [TypeDescriptor java.lang.Boolean] to [TypeDescriptor java.lang.Boolean]
03:45:14.599 [7225609@qtp-10131947-7] TRACE o.s.c.c.s.GenericConversionService - Matched cached converter NO_OP
03:45:14.599 [7225609@qtp-10131947-7] DEBUG o.s.c.c.s.GenericConversionService - Converted to false
03:45:14.599 [7225609@qtp-10131947-7] DEBUG o.s.s.access.vote.AffirmativeBased - Voter: org.springframework.security.access.prepost.PreInvocationAuthorizationAdviceVoter@a866a9, returned: -1
03:45:14.599 [7225609@qtp-10131947-7] DEBUG o.s.s.access.vote.AffirmativeBased - Voter: org.springframework.security.access.vote.RoleVoter@1ebf305, returned: 0
03:45:14.599 [7225609@qtp-10131947-7] DEBUG o.s.s.access.vote.AffirmativeBased - Voter: org.springframework.security.access.vote.AuthenticatedVoter@19ffd6f, returned: 0

    我真的不知道在哪里继续调试。我错过了什么？我是否必须创建自己的记住我的实现？

    我真的欣赏一个演示弹簧默认实现的工作示例应用程序，记住我...

    --------编辑-----------

    我刚刚编译并运行了springsecurity本身的remember-me参考应用程序：spring-security\samples\tutorial帐户应用和联系人应用。实际上，我有完全相同的问题？！？。我试过火狐，歌剧等等......我被打碎了......

2 个答案:

答案 0 :(得分：1)

看起来mem-me身份验证在您的应用程序中正常运行，因为您从remember-me cookie中获取了有效的身份验证令牌。

但是，日志输出表明控制器方法bstController.showbstpage上存在方法访问控制注释，该方法需要从表达式isFullyAuthenticated() and #username == principal.username进行“完全”身份验证。记住，我没有资格作为完全身份验证，因此表达式拒绝当前身份验证。

除此之外，intercept-url元素的排序错误，因为/**位于顶部，并将应用于所有请求，使其他请求变得多余。

此外，不可能在示例应用程序中遇到相同的问题，因为它们不需要对任何操作进行完全身份验证，因此您必须遇到其他问题。

答案 1 :(得分：0)

登录时，UserDetails对象上的“password”字段是否设置为非null /非空值？在我的应用程序中，实际身份验证被委托给另一个系统，我不会将用户提交的密码存储在我的UserDetails对象上。在将password属性设置为值之前，我无法使RememberMe cookie生效。在我的情况下，我只是将属性默认为“密码”这个词，因此它不会是空/空字符串。

我不知道这与你的情景有什么关系，但这让我疯狂，直到我弄明白。

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