Question

我有一个表，其中包含一个基于其他几个字段的concatenatedTerm字段。根据“名称”字段中的特定值，串联会发生不同的情况，例如

Update Table1 Set ConcatField = concat(Field1,' ',field2) where Name=1;
Update Table1 Set ConcatField = concat(Field1,' ',field2,' ',field3) where Name=2'

为了论证，让我们说Name = 1与First和Last联合，例如John Smith和名称= 2与Honorific First Last的联合，例如Dr. Joe Blow

我试图通过第二个包含Name和Concat字段的表来强制执行此操作。这个想法是我可以制作像

这样的唱片

Table2:Name=1, Table2:Concat=First,' ',Last

然后是单个更新语句，如：

Update Table1 as T1
Inner Join Table2 as T2
On T1.Name=T2.Name
Set T1.ConcatField=T2.Concat

因为Table2已经与其他Name特定数据一起存在，我认为这将允许我简单地向Table2添加Table1 Concats更新的方式，而不必继续更新Table1 Update语句，只需添加Table2，无论如何。

然而，显然问题是update语句正在从T2.Concat中推送实际的字符串，例如所有Name1记录只需获得First Last作为Concat值

=Concact(T2.Concat)

仍然得到同样的错误。所以问题是如何将Table2中的字符串值推送到Table2的更新值中，它实际上是指Table1中的字段？

添加了表格示例 *(note this is not the actual tables or data so I understand in this simple case the solution I'm looking for could be obtained a lot easier, just trying to add simple common table as example)*

表1：

+-----------+-------+--------+------------+
| Honorific | First | Last   | SearchTerm |
+-----------+-------+--------+------------+
| Mr.       | Joe   | Smith  |            |
+-----------+-------+--------+------------+
| Mrs.      | Jane  | Doe    |            |
+-----------+-------+--------+------------+
| Dr.       | Bob   | Rogers |            |
+-----------+-------+--------+------------+

期望输出：

+-----------+-------+--------+-----------------+
| Honorific | First | Last   | SearchTerm      |
+-----------+-------+--------+-----------------+
| Mr.       | Joe   | Smith  | Joe Smith       |
+-----------+-------+--------+-----------------+
| Mrs.      | Jane  | Doe    | Jane Doe        |
+-----------+-------+--------+-----------------+
| Dr.       | Bob   | Rogers | Dr. Bob Rodgers |
+-----------+-------+--------+-----------------+

表2：

+-----------+----------+----------------------+
| Honorific | FullTerm | Concat               |
+-----------+----------+----------------------+
| Mr.       | Mister   | First,Last           |
+-----------+----------+----------------------+
| Mrs.      | Misses   | First,Last           |
+-----------+----------+----------------------+
| Dr.       | Doctor   | Honorific,First,Last |
+-----------+----------+----------------------+

请注意，我真的希望Concat成为第一个，＆＃39; ＆＃39;，最后但表格生成器不喜欢没有粘贴的引号。

所以这个想法是：

Update Table1 as T1
Inner Join Table2 as T2
On T1.Name=T2.Name
Set T1.SearchTerm=T2.Concat

相当于：

Update Table1 as T1
Inner Join Table2 as T2
On T1.Name=T2.Name
Set T1.SearchTerm=Case
When T2.Name='Dr.' Then Concat(T1.Honorific,T1.First,T1.Last)
Else Concat(T1.First,T1.Last)

并产生与所需输出相同的输出，但它很简单：

+-----------+-------+--------+-----------------------+
| Honorific | First | Last   | SearchTerm            |
+-----------+-------+--------+-----------------------+
| Mr.       | Joe   | Smith  | First,Last            |
+-----------+-------+--------+-----------------------+
| Mrs.      | Jane  | Doe    | First,Last            |
+-----------+-------+--------+-----------------------+
| Dr.       | Bob   | Rogers | Honorific,Search,Last |
+-----------+-------+--------+-----------------------+

换句话说，当我希望它用字段填充Concat语句时，它会将表2中的实际字符串推送到TableT的SearchTerm。

使用另一个表中的值更新一个表中的concat语句？

0 个答案: