我需要从一些xml的日志中擦除一些数据,我需要知道如何使preg_replace替换所有正则表达式匹配的出现。
xml看起来像这样。
<contactData>
<id>29194</id>
<firstName>Michael</firstName>
<lastName>Smith</lastName>
<address1>1600 Pennsylvania Ave</address1>
<address2></address2>
<city>Washington</city>
<state>DC</state>
<postalCode>20500</postalCode>
<country>US</country>
<phone>3012013021</phone>
<email>michael@potus.gov</email>
</contactData>
<contactData>
<id>29195</id>
<firstName>Shelly</firstName>
<lastName>McPherson</lastName>
<address1>2411 Georgia Ave</address1>
<address2></address2>
<city>Silver Spring</city>
<state>MD</state>
<postalCode>20902-5412</postalCode>
<country>US</country>
<phone>3012031302</phone>
<email>shelly@example.com</email>
</contactData>
当我在这个xml上运行它时。
$regex = $replace = array();
$regex[] = '/(<contactData>)(.*)(<email>)(.*)(<\/email>)/is';
$regex[] = '/(<contactData>)(.*)(<phone>)(.*)(<\/phone>)/is';
$replace[] = '$1$2$3xxxxxxxxxxxxxxxx$5';
$replace[] = '$1$2$3xxxxxxxxxxxxxxxx$5';
$text = preg_replace($regex, $replace, $text);
我明白了。
<contactData>
<id>29194</id>
<firstName>Michael</firstName>
<lastName>Smith</lastName>
<address1>1600 Pennsylvania Ave</address1>
<address2></address2>
<city>Washington</city>
<state>DC</state>
<postalCode>20500</postalCode>
<country>US</country>
<phone>3012013021</phone>
<email>michael@potus.gov</email>
</contactData>
<contactData>
<id>29195</id>
<firstName>Shelly</firstName>
<lastName>McPherson</lastName>
<address1>2411 Georgia Ave</address1>
<address2></address2>
<city>Silver Spring</city>
<state>MD</state>
<postalCode>20902-5412</postalCode>
<country>US</country>
<phone>xxxxxxxxxxxxxxxx</phone>
<email>xxxxxxxxxxxxxxxx</email>
</contactData>
如何更换其他“contactData”电子邮件和手机?
答案 0 :(得分:2)
使用任何XML解析器执行此操作更为正确。例如,simpleXML
// Your XML does not inlude root element.
// If real does, remove `root`from the next line
$xml = simplexml_load_string('<root>' . $text . '</root>');
for($i = 0; $i < count($xml->contactData); $i++) {
unset($xml->contactData[$i]->email);
unset($xml->contactData[$i]->phone);
}
echo $xml->saveXML();