在具有不同文本长度的字符串中替换不同长度的数字

时间:2016-05-25 12:05:16

标签: ios string swift2.2 nsscanner

问题:不同长度的数字可以是1,200,1000,39,99995等。并且需要替换为文本,例如。 “Apple”,它与数值不同。

让str:String =“你好我有10个字符串类的1313个对象,有1个对象,类似于9999个错误”

预期结果=“你好 Apple Apple 字符串类的对象 Apple 对象,类似于 Apple 错误“

我尝试使用以下代码:

 var originalString: String = "hello i have 1313 object of 10 string class with 1 object, similar to 9999 errors"

    let strippedString: NSMutableString = NSMutableString(capacity: originalString.characters.count)
    var numArray: [String] = []
    var locArray: [NSNumber] = []
    var scanner: NSScanner = NSScanner(string:originalString)
    let numbers: NSCharacterSet = NSCharacterSet(charactersInString: "0123456789")
    while scanner.atEnd == false {
        var buffer: NSString?
        if scanner.scanCharactersFromSet(numbers, intoString: &buffer) {
            strippedString.appendString(buffer! as String)
            numArray.append(buffer! as String)
            locArray.append(scanner.scanLocation)
        }
        else {

            scanner.scanLocation = (scanner.scanLocation + 1)
        }
    }
    for (index, _) in numArray.enumerate() {
        var loc : Int = Int(locArray[index] ) - (String(numArray[index]).characters.count)
        let len = String(numArray[index]).characters.count
        let dupStr = "Apple"
        if(index != 0 && len !=  dupStr.characters.count)
        {
            loc = loc + (dupStr.characters.count - len) + 1
        }
        originalString.replaceRange(originalString.startIndex.advancedBy(loc)..<originalString.startIndex.advancedBy(loc + len), with: dupStr)
    }
    print(originalString)

2 个答案:

答案 0 :(得分:0)

Swift 2

NSScanner很棒,但如果您想要一个更简单的解决方案来完成此任务,您可以使用componentsSeparatedByStringmapInt()joinWithSeparator,如下所示:

let originalString = "hello i have 1313 object of 10 string class with 1 object, similar to 9999 errors"
let tokens = originalString.componentsSeparatedByString(" ")
let newTokens = tokens.map { (token) -> String in
    if let _ = Int(token) {
        return "Apple"
    }
    return token
}
let result = newTokens.joinWithSeparator(" ")
print(result)

打印:

  

你好我有Apple对象的Apple对象Apple对象,类似于Apple错误

还有一个用于映射的简短版本:

let newTokens = tokens.map { Int($0) != nil ? "Apple" : $0 }

Swift 3

componentsSeparatedByString(_:)现在是components(separatedBy:)joinWithSeparator(_:)现在是joined(separator:)

let tokens = originalString.components(separatedBy: " ")
let newTokens = tokens.map { Int($0) != nil ? "Apple" : $0 }
let result = newTokens.joined(separator: " ")

答案 1 :(得分:-1)

var str: String = "hello i have 1313 object of 10 string class with 1 object, similar to 9999 errors"
var comp: [AnyObject] = [AnyObject](array: str.componentsSeparatedByString(" "))
for var i = 0; i < comp.count; i++ {
  var numberRegex: NSRegularExpression = NSRegularExpression.regularExpressionWithPattern("^[0-9]", options: NSRegularExpressionCaseInsensitive, error: nil)
  var regexMatch: Int = numberRegex.numberOfMatchesInString(comp[i], options: 0, range: NSMakeRange(0, (String(comp[i])).length))
    if regexMatch != 0 {
      comp[i] = "Apple"
    }
}
var result: String = comp.componentsJoinedByString(" ")
print(result)