Question

这里混合了HTML和PHP。我没有将它们分开，因为标签是由php填充的。

    <form method="post">
    <select name="Select User" value="Select User">
    <?php
    $sth = $conn->prepare('Select username From users');
    $sth->execute();
    $data = $sth->fetchAll();   
    foreach ($data as $row ){
        if($row['username']!="")
    echo " <option id=\"Select_user\" name=\"Select_user\" value=\"Select_user\">".$row['username']."</option>";
    }
    ?>

    </select><br>
    <input type="submit" name="submit" value="Delete"</input>

    <?php
           if(! empty($_POST['Select_user']))
           {
            $del_user=$_POST['Select_user'];
            $sql = "DELETE FROM users WHERE username=:del";
            $sth = $conn->prepare($sql);
            $sth->execute(array(':del'=>$del_user));
           }

    ?>

下拉列表正在正确获取数据，但删除操作没有发生。为什么呢？

Answer 1

您需要在将在php中发布的选项值中设置正确的数据，选择的选项值将被发布，因此您需要$ _POST中的用户名，因此在选项值中设置用户名：

<form method="post">
    <select name="user_selection">

    <?php
        $sth = $conn->prepare('Select username From users');
        $sth->execute();


   $data = $sth->fetchAll();   
    foreach ($data as $row ){
        if($row['username']!="")
        echo '<option id="Select_user" name="Select_user" value="'.$row["username"].'">'.$row["username"].'</option>';
    }
    ?>

    </select><br>
    <input type="submit" name="submit" value="Delete"</input>

    <?php
           if(! empty($_POST['user_selection'])) // access element by its name
           {
            $del_user=$_POST['user_selectio'];
            $sql = "DELETE FROM users WHERE username=:del";
            $sth = $conn->prepare($sql);
            $sth->execute(array(':del'=>$del_user));
           }

    ?>

下拉数据不是从数据库中删除

1 个答案: