Question

我正在使用准备segue在视图控制器之间发送数据，当标识符是“ShowPost”时，第一个if条件工作并将url发送到视图控制器。但是当标识符是“profileInfo”时，segue不发送数据。

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
  if segue.identifier == "ShowPost" {
    if let indexPath = tableView.indexPathForSelectedRow {
      let _url = searchResults[indexPath.row]["link"].stringValue
      let destinationController = segue.destinationViewController as! ShowPostViewController
      destinationController.url = _url
    }
    else if segue.identifier == "ProfileInfo" {
      if let indexPath = tableView.indexPathForSelectedRow {
        let _userName = searchResults[indexPath.row]["owner"]["display_name"].stringValue
        // print("name dc: \(destinationController.userName)")
        let _userId = searchResults[indexPath.row]["owner"]["user_id"].stringValue
        let _userReputation = searchResults[indexPath.row]["owner"]["reputation"].stringValue
        let _ppImageString = searchResults[indexPath.row]["owner"]["profile_image"].stringValue
        let destinationController = segue.destinationViewController as! ProfileInfoViewController
        destinationController.userName = _userName
        destinationController.userId = _userId
        destinationController.userReputation = _userReputation
        destinationController.ppImageString = _ppImageString
      }
    }
  }
}

Answer 1

else语句被添加到第一个if语句中，并且无法运行。

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
    if segue.identifier == "ShowPost" {
        if let indexPath = tableView.indexPathForSelectedRow {
            let _url = searchResults[indexPath.row]["link"].stringValue
            let destinationController = segue.destinationViewController as! ShowPostViewController
            destinationController.url = _url
        }


    }
     else if segue.identifier == "ProfileInfo" {

            if let indexPath = tableView.indexPathForSelectedRow {

                let _userName = searchResults[indexPath.row]["owner"]["display_name"].stringValue
                // print("name dc: \(destinationController.userName)")
                let _userId = searchResults[indexPath.row]["owner"]["user_id"].stringValue
                let _userReputation = searchResults[indexPath.row]["owner"]["reputation"].stringValue
                let _ppImageString = searchResults[indexPath.row]["owner"]["profile_image"].stringValue
                let destinationController = segue.destinationViewController as! ProfileInfoViewController
                destinationController.userName = _userName
                destinationController.userId = _userId
                destinationController.userReputation = _userReputation
                destinationController.ppImageString = _ppImageString


            }
        }

}

Answer 2

你的else语句在if语句中，所以永远不会被执行。

所以，将另一个if语句分开。

确保您已从界面构建器中设置了正确的标识符和类。

Answer 3

 override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
        if segue.identifier == "ShowPost" {
            if let indexPath = tableView.indexPathForSelectedRow {
                let _url = searchResults[indexPath.row]["link"].stringValue
                let destinationController = segue.destinationViewController as! ShowPostViewController
                destinationController.url = _url
            }
        }
            else if segue.identifier == "ProfileInfo" {
                if let indexPath = tableView.indexPathForSelectedRow {
                    let _userName = searchResults[indexPath.row]["owner"]["display_name"].stringValue
                    // print("name dc: \(destinationController.userName)")
                    let _userId = searchResults[indexPath.row]["owner"]["user_id"].stringValue
                    let _userReputation = searchResults[indexPath.row]["owner"]["reputation"].stringValue
                    let _ppImageString = searchResults[indexPath.row]["owner"]["profile_image"].stringValue
                    let destinationController = segue.destinationViewController as! ProfileInfoViewController
                    destinationController.userName = _userName
                    destinationController.userId = _userId
                    destinationController.userReputation = _userReputation
                    destinationController.ppImageString = _ppImageString
                }
            }

    }

Answer 4

使用Switch可能会更清楚一点：

switch segue.identifier ?? "" {
    case "ShowPost":
        if let indexPath = tableView.indexPathForSelectedRow {
            let _url = searchResults[indexPath.row]["link"].stringValue
            let destinationController = segue.destinationViewController as! ShowPostViewController
            destinationController.url = _url
        }
    case "ProfileInfo":
        if let indexPath = tableView.indexPathForSelectedRow {

            let _userName = searchResults[indexPath.row]["owner"]["display_name"].stringValue
            // print("name dc: \(destinationController.userName)")
            let _userId = searchResults[indexPath.row]["owner"]["user_id"].stringValue
            let _userReputation = searchResults[indexPath.row]["owner"]["reputation"].stringValue
            let _ppImageString = searchResults[indexPath.row]["owner"]["profile_image"].stringValue
            let destinationController = segue.destinationViewController as! ProfileInfoViewController
            destinationController.userName = _userName
            destinationController.userId = _userId
            destinationController.userReputation = _userReputation
            destinationController.ppImageString = _ppImageString
    }
    default: break
}

准备segue不工作的多个条件

4 个答案: