Question

我的下拉列表存在问题。当我在下拉列表中按某些东西时，它将填满我的桌子，我没有在这里显示。但我想要的是下拉列表必须保存我按下的东西并给自己起名。我真的不知道该怎么做。

看看这个how to hold a selected list value after clicking go button?。

我的代码：

<form id="form" method="post" class="form-inline">
                <div class="form-group">
                    <label for='Select'>head:</label>
                    <select  class="form-control" onchange="this.form.submit()">
                    <?php
                            //My $con is someone where else.
                            $resultName = $con->query("SELECT * FROM ond");                             
                            while ($row = $resultName->fetch_assoc()) {
                                            echo '<option value="'.$row["ondID"].'">'.$row['Name'].'</option>'; 
                                    }                               
                    ?>
                    </select>                               
                </div>  
            </div>  
        </form>

Answer 1

如果要为下拉列表指定名称。这是我根据上述评论理解的。

 <select class="form-control" name="anyname" onchange="this.form.submit()">
   <!--Rest of the code-->
 </select>

Answer 2

根据您的评论，我了解您希望选择下拉选项值与onchange()事件。

function check(val)
{
	alert(val);
}

<form id="form" method="post" class="form-inline">
	<div class="form-group">
		<label for='Select'>head:</label>
		<select  class="form-control" onchange="check(this.value)">
			<option value="test">Test</option>
			<option value="test1">Test1</option>
		</select>                               
	</div>  
</div>  
</form>

Answer 3

请试试这个

<script>
function getDropdownVal(val){
	alert(val);
}

</script>

<form id="form" method="post" class="form-inline">
                <div class="form-group">
                    <label for='Select'>head:</label>
                    <select  class="form-control" onchange="getDropdownVal(this.value)">
                    <?php
                            //My $con is someone where else.
                            $resultName = $con->query("SELECT * FROM ond");                             
                            while ($row = $resultName->fetch_assoc()) {
                                            echo '<option value="'.$row["ondID"].'">'.$row['Name'].'</option>'; 
                                    }                               
                    ?>
                    </select>                               
                </div>  
            </div>  
        </form>

Answer 4

希望这适合你

<form id="form" method="post" class="form-inline">
            <div class="form-group">
                <label for='Select'>head:</label>

                <select class="form-control" id="search" type="select" value="<?php echo $form-control ?>" onchange="this.form.submit()">
                <option selected="selected"><?php echo "{$_POST['search']} "; ?></option>
                  <option>Example 1</option>
                  <option>Example 2</option>
                  <option>Example 3</option>
                <?php
                        //My $con is someone where else.
                        $resultName = $con->query("SELECT * FROM `table` where `Name`");                             
                        while ($row = $resultName->fetch_assoc()) {
                                        echo '<option value="'.$row["ondID"].'">'.$row['Name'].'</option>'; 
                                }                               
                ?>
                </select>                               
            </div>  
        </div>  
    </form>

Answer 5

使用以下代码

didChangeSection

在您的代码中：

<?php $selectedValue = isset($_POST['selectName']) ? $_POST['selectName']: ""; ?>
<form id="form" method="post" class="form-inline">
    <div class="form-group">
        <label for='Select'>head:</label>
        <select name="selectName" class="form-control" onchange="this.form.submit()">
            <option value="">SELECT</option>
            <option <?php if ($selectedValue=='test') echo 'selected="selected"';?> value="test">Test</option>
            <option <?php if ($selectedValue=='test1') echo 'selected="selected"';?> value="test1">Test1</option>
        </select>                               
    </div>  
</div>  
</form>
<?php if($selectedValue) echo "You have select <strong>" . $selectedValue . "</strong>"; ?>

将名称设置为数据库中的下拉列表？

5 个答案: