Question

我在Hibernate中有一个希望很简单的问题。我有用户和项目。 users_projects（在我的例子中是user_project_association）有一个额外的属性＆＃34; role＆＃34;说用户是项目负责人还是普通用户。

@OneToMany(mappedBy = "project", cascade = CascadeType.ALL, orphanRemoval = true, fetch = FetchType.LAZY)
@LazyCollection(LazyCollectionOption.EXTRA)
private Set<UserProjectAssociation> userProjectAssociations = new HashSet<>();

@ManyToMany(fetch = FetchType.EAGER)
@JoinTable(name = "user_project_role",
        joinColumns = @JoinColumn(name = "project_id", referencedColumnName = "id"),
        inverseJoinColumns = @JoinColumn(name = "user_id", referencedColumnName = "id"))
@WhereJoinTable(clause = "role_id=7")
@Setter(AccessLevel.NONE)
private Set<User> projectLeaders = new HashSet<>();

@ManyToMany
@JoinTable(name = "user_project_role",
        joinColumns = @JoinColumn(name = "project_id", referencedColumnName = "id"),
        inverseJoinColumns = @JoinColumn(name = "user_id", referencedColumnName = "id"))
@LazyCollection(LazyCollectionOption.EXTRA)
@Setter(AccessLevel.NONE)
private Set<User> users = new HashSet<>();

如果我尝试通过＆＃34; getEntityManager（）删除项目.remove（persistentInstance）;＆＃34;我可以在日志中看到这个sql语句：

Hibernate: 
/* delete collection com.XXX.core.model.Project.users */ delete 
    from
        user_project_role 
    where
        project_id=?
Hibernate: 
/* delete collection com.XXX.core.model.Project.projectLeaders */ delete 
    from
        user_project_role 
    where
        project_id=? 
        and (
            role_id=7
        ) 
Hibernate: 
/* delete com.XXX.core.model.UserProjectAssociation */ delete 
    from
        user_project_role 
    where
        id=?

和错误消息：

2016-05-25 10:05:57 INFO  AbstractBatchImpl:208 - HHH000010: On release of batch it still contained JDBC statements

并且没有删除任何内容。有没有人有想法删除我的项目？

非常感谢：）

Answer 1

PUH。我找到了（或者）解决方案。它并不是很优雅，但它有效：

@ManyToMany(fetch = FetchType.EAGER)
@JoinTable(name = "user_project_role",
        joinColumns = @JoinColumn(name = "project_id", referencedColumnName = "id"),
        inverseJoinColumns = @JoinColumn(name = "user_id", referencedColumnName = "id"))
@WhereJoinTable(clause = "role_id=7")
@SQLInsert(sql = "insert into user_project_role (project_id, user_id, role_id) values (?, ?, 7)")
@SQLDelete(sql = "delete from user_project_role where project_id=? and user_id=? and role_id = 7")
@Setter(AccessLevel.NONE)
private Set<User> projectLeaders = new HashSet<>();

@ManyToMany
@JoinTable(name = "user_project_role",
        joinColumns = @JoinColumn(name = "project_id", referencedColumnName = "id"),
        inverseJoinColumns = @JoinColumn(name = "user_id", referencedColumnName = "id"))
@LazyCollection(LazyCollectionOption.EXTRA)
@WhereJoinTable(clause = "role_id=8")
@SQLInsert(sql = "insert into user_project_role (project_id, user_id, role_id) values (?, ?, 8)")
@Setter(AccessLevel.NONE)
private Set<User> projectUsers = new HashSet<>();

所以我删除了userProjectAssociations属性并添加了自定义的@SQLInsert和@SQLDelete语句。

如果我想让所有用户包括普通用户和项目负责人，我会使用这种方法：

public Set<User> getAllUsers() {
    Set<User> allUsers = new HashSet<>();
    allUsers.addAll(projectLeaders);
    allUsers.addAll(projectUsers);
    return allUsers;
}

Hibernate多个属性映射相同的表删除

1 个答案: