这是我当前的查询(来自here)
select a.No_Registrasi, a.Nama_CTKI, b.Nama_Negara, CONCAT('RA-', MAX(substring(c.ID_Rad, 4) + 0)) AS ID_Rad, CONCAT('Lab-',MAX(substring(d.ID_Lab, 5) + 0)) AS Id_Lab
FROM tb_registrasi a
JOIN tb_negara_tujuan b
ON a.ID_Negara = b.ID_Negara
JOIN tb_radiologi c
ON a.No_Registrasi = c.No_Registrasi
JOIN tb_laboratorium d
ON a.No_Registrasi = d.No_Registrasi
GROUP BY a.No_Registrasi, a.Nama_CTKI, b.Nama_Negara
我如何得到我期待的结果?我在这样的高级查询中真的没有经验,任何帮助都是非常苛刻的。谢谢。
答案 0 :(得分:1)
希望这有帮助。
select a.No_Registrasi, a.Nama_CTKI, b.Nama_Negara, CONCAT('RA-', MAX(substring(c.ID_Rad, 4) + 0)) AS ID_Rad, CONCAT('Lab-',MAX(substring(d.ID_Lab, 5) + 0)) AS Id_Lab
FROM tb_registrasi a
LEFT JOIN tb_negara_tujuan b
ON a.ID_Negara = b.ID_Negara
LEFT JOIN tb_radiologi c
ON a.No_Registrasi = c.No_Registrasi
LEFT JOIN tb_laboratorium d
ON a.No_Registrasi = d.No_Registrasi
GROUP BY a.No_Registrasi, a.Nama_CTKI, b.Nama_Negara