Question

我试图制作一个用电脑玩摇滚，纸，剪刀的程序。但是，部分任务是让玩家选择与计算机一起玩的轮数。如果有平局，则该轮不应计入比赛。

我的代码看起来像这样 - 我更关注程序的for部分：

int gamePlays = 0;

for (int = 0; i < gamePlays; i++)
{
 // If, else if, and else statements to make the game possible. 
 // Here is an example of part of the code:
if (cpuChoice.equals ("rock"))
{
  if (userChoice.equals ("scissors"))
  {
      System.out.println("Rock beats scissors, computer wins.");
  }
  else if (userChoice.equals ("paper"))
  {
      System.out.println("Paper beats rock, computer wins.");
  }
  else 
  {
      System.out.println("You both chose rock! It's a tie.");
  }
// The rest would else if cpuChoice.equals "paper" and else. 
}

如果从计数器获得平局，我如何排除最后else声明？我已经和我搏斗了几个小时，无法找到任何解决方案。

Answer 1

而不是08:23:22,041 [-] [Siddhi-R_H_Match-executor-thread-1] INFO TenantId : -1234, Event Processor : R_H_Match, Event Stream : matchingStream:1.0.0 (ms), after processing _[Event{timestamp=1464144801945, data=[27, phone, g1, sell, samsung, galaxy note, type, 16, phone, g1, buy, samsung, galaxy note, type], isExpired=false}] (Sanitized) 08:23:22,120 [-] [Siddhi-R_H_Match-executor-thread-1] INFO TenantId : -1234, Event Processor : R_H_Match, Event Stream : matchingStream:1.0.0 (ms), after processing _[Event{timestamp=1464144802037, data=[27, phone, g1, sell, samsung, galaxy note, type, 16, phone, g1, buy, samsung, galaxy note, type], isExpired=false}] (Sanitized)我建议@Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); SetIP setip = new SetIP(); setip.hello(); }

for

}

Answer 2

您的for循环会创建一个变量i，您可以在for循环的主体中修改该变量。如果您希望代码在用户与CPU绑定时具有 not 递增计数器的效果，则在您需要的位置递减i：

int gamePlays = 0
for (int i = 0; i < gamePlays; i++) {
   ...
   else {
     // this is where you handle ties
     System.out.println("You tied with CPU");
     i--; // decrement the counter
   }
   ...
}

Answer 3

如果发生这种情况，请填写

i--;

该声明。然后这轮不包括在内。对于你的问题。

for (int = 0; i < gamePlays; i++)
{
 // If, else if, and else statements to make the game possible. 
 // Here is an example of part of the code:
if (cpuChoice.equals ("rock"))
{
  if (userChoice.equals ("scissors"))
  {
      System.out.println("Rock beats scissors, computer wins.");
  }
  else if (userChoice.equals ("paper"))
  {
      System.out.println("Paper beats rock, computer wins.");
  }
  else 
  {
      System.out.println("You both chose rock! It's a tie.");
      i--;
  }
// The rest would else if cpuChoice.equals "paper" and else. 
}

这将使＆＃39; i＆＃39;保持不变，因为你的“我”是将在循环后递增。

Answer 4

首先，你的消息是错误的。当cpuChoice.equals("rock")和userChoice.equals("paper")时，正确的消息是：

Paper beats rock， player 获胜。

此外，如果gamePlays = 0，则不会有游戏。 ; - ）

由于您可能也希望保持得分，只需使用分数：

int cpuWins = 0;
int userWins = 0;
while (cpuWins + userWins < gamePlays) {
    if (cpuChoice.equals("rock")) {
        if (userChoice.equals("scissors")) {
            System.out.println("Rock beats scissors, computer wins.");
            cpuWins++;
        } else if (userChoice.equals("paper")) {
            System.out.println("Paper beats rock, player wins.");
            userWins++;
        } else {
            System.out.println("You both chose rock! It's a tie.");
        }
    } else ...
        ...
    }
}
if (cpuWins > userWins)
    System.out.println("Computer is champion.");
else if (cpuWins < userWins)
    System.out.println("Player is champion.");
else
    System.out.println("There is no champion.");

我可以在for循环中对计数器进行异常处理吗？

4 个答案: