我们必须为我的AP计算机科学课完成一项任务，并且我想出了代码的基础，但我被困在了一部分。如果您想尝试一下，这是完成作业的链接。
LINK：http://codingbat.com/prob/p254067
到目前为止，这是我的代码：
public int numVworthy(String wordsList[]) {
int count = 0;
String w = "w";
String v = "v";
for(int i = 0; i < wordsList.length; i++) {
if(wordsList[i].contains(v) && wordsList.length - 1 == 0) {
count++;
}
if(wordsList[i].contains(v) && i == 0) {
if(!wordsList[i + 1].contains(w)) {
count++;
}
}
if(wordsList[i].contains(v) && i == wordsList.length - 1) {
if(!wordsList[i - 1].contains(w)) {
count++;
}
}
}
return count;
}
答案 0 :(得分：0)
您正在使用的语法是incorect
应该是
if(wordsList[i].contains(v)) {
答案 1 :(得分：0)
此代码应该可以使用
public int numVworthy(String wordsList[]) {
int count = 0;
String w = "w";
String v = "v";
for(int i = 0; i < wordsList.length; i++) {
// first we check the final decision: does the word contain v or not
if(wordsList[i].contains(v)){
// then we check if there's only one word, since this is a special case, where it'll always count
if(wordsList.length == 1){
count++;
}
// otherwise we'll see if the previous word contains a w
// if there is a previous word
else if(i>0 && !wordsList[i-1].contains(w)){
// if the previous word doesn't contain a w we'll see if the next
// word contains a w, if there is a next word
if((i+1)<wordsList.length && !wordsList[i+1].contains(w)){
// all conditions are satisfied
count++;
// if there isn't a next word all conditions have been satisfied
} else if(i==(wordsList.length - 1)){
count++;
}
// if there isn't a previous word, the only condition is that the next
// word doesn't contain a w
} else if(i==0 && (i+1)<wordsList.length && !wordsList[i+1].contains(w)){
count++;
}
}
}
return count;
}
我希望你觉得这很有帮助这个练习是一个贯穿所有场景的问题，在这种情况下：
答案 2 :(得分：-1)
试试这个
enter code here
public int numVworthy(String wordsList[]) {
int count = 0;
String w = "w";
String v = "v";
bool prevw = false;
bool flagv = false;
for(int i = 0; i < wordsList.length; i++) {
if(!wordsList[i].contains(w) && !prevw) {
prevw = true;
}else if(wordsList[i].contains(v) && !flagv && prevw) {
flagv= true;
}
else if(!wordsList[i].contains(w) && flagv)
{
count++;
}
else
{
prevw=nextw=flagv= false;
i=-2; // used to recheck this line for prev two that are excaped beacuse of the prevw flag is true
}
}
return count;
}
答案 3 :(得分：-1)
此代码工作正常！只使用一个if。
"""
This script will submit current file to deadline for render
"""
import os
import sys
import subprocess
import maya.cmds as cmds
def maya_deadline_job():
"""
this function will collect scene file information and write a job file
:return:
"""
renderer_name = 'File'
version = cmds.about(version=True)
project_path = cmds.workspace(q=True, directory=True)
width = cmds.getAttr("defaultResolution.width")
height = cmds.getAttr("defaultResolution.height")
output_file_path = cmds.workspace(expandName="images")
output_file_prefix = cmds.getAttr("defaultRenderGlobals.imageFilePrefix")
scene_file = cmds.file(q=True, location=True)
info_txt = 'Animation=1\n' \
'Renderer={}\n' \
'UsingRenderLayers=0\n' \
'RenderLayer=\n' \
'RenderHalfFrames=0\n' \
'LocalRendering=0\n' \
'StrictErrorChecking=1\n' \
'MaxProcessors=0\n' \
'AntiAliasing=low\n' \
'Version={}\n' \
'Build=64bit\n' \
'ProjectPath={}\n' \
'ImageWidth={}\n' \
'ImageHeight={}\n' \
'OutputFilePath={}\n' \
'OutputFilePrefix={}\n' \
'Camera=\n' \
'Camera0=\n' \
'Camera1=RENDERShape\n' \
'Camera2=frontShape\n' \
'Camera3=perspShape\n' \
'Camera4=sideShape\n' \
'Camera5=topShape\n' \
'SceneFile={}\n' \
'IgnoreError211=0'.format(renderer_name
version,
project_path,
width,
height,
output_file_path,
output_file_prefix,
scene_file)
maya_deadline_job_file = r'{}\maya_deadline_job.job'.format(os.getenv('TEMP'))
with open(maya_deadline_job_file, 'w') as job_file:
job_file.write(info_txt)
return maya_deadline_job_file
def maya_deadline_info():
"""
this function will collect maya deadline information and write a job file
:return:
"""
info_txt = 'Plugin=MayaBatch\n' \
'Name=MY_FILE_NAME\n' \
'Comment=Render Launch by Python\n' \
'Pool=none\n' \
'MachineLimit=0\n' \
'Priority=50\n' \
'OnJobComplete=Nothing\n' \
'TaskTimeoutMinutes=0\n' \
'MinRenderTimeMinutes=0\n' \
'ConcurrentTasks=1\n' \
'Department=\n' \
'Group=none\n' \
'LimitGroups=\n' \
'JobDependencies=\n' \
'InitialStatus=Suspended\n' \
'OutputFilename0=C:/Users/raijv/Documents/maya/projects/default/images/masterLayer_2.iff.????\n' \
'Frames=1-10\n' \
'ChunkSize=1'
maya_deadline_info_file = r'{}\maya_deadline_info.job'.format(os.getenv('TEMP'))
with open(maya_deadline_info_file, 'w') as job_file:
job_file.write(info_txt)
return maya_deadline_info_file
def submit_to_deadline():
"""
this function will send current scene to deadline for rendering
:return:
"""
deadline_cmd = r"C:\Program Files\Thinkbox\Deadline\bin\deadlinecommand.exe"
job_file = maya_deadline_job()
info_file = maya_deadline_info()
command = '{deadline_cmd} "{job_file}" "{info_file}"'.format(**vars())
process = subprocess.Popen(command, stdout=subprocess.PIPE)
lines_iterator = iter(process.stdout.readline, b"")
# Lets print the output log to see the Error / Success
for line in lines_iterator:
print(line)
sys.stdout.flush()
submit_to_deadline()