我正在练习如何在c ++中创建一个链表,并在下面发布代码。我分配内存错了吗?我不确定它是否是导致错误的节点或列表的构造函数,但我不断收到细分错误。我是初学者,我真的想要很好地理解内存分配。
main.cpp中:
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <string>
#include "list.h"
using namespace std;
int main(void)
{
int option;
list *linked;
linked = new list;
while(1)
{
// menu
cout<<"********************************************"<<endl;
cout<<" what option would you like to use "<<endl;
cout<<" 1.add a node"<<endl;
cout<<" 2.show list"<<endl;
cout<<" 3.delete node"<<endl;
cout<<"********************************************"<<endl;
cin>>option;
//switch for option
switch(option)
{
case 1 :
cout<<"you picked add a node"<<endl;
(*linked).add_node();
break;
case 2 :
cout<<"you picked show list"<<endl;
break;
case 3 :
cout<<"you picked delete node"<<endl;
break;
default:
cout<<"thats not a valid option"<<endl;
break;
}
}
return 0;
}
list.h:
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <string>
using namespace std;
class node
{
private:
node *next;
node *prev;
string note;
public:
// constructor
node();
//gets
node* get_next(void)
{return next;}
node* get_prev(void)
{return prev;}
// setts
void set_next(node* x)
{next=x;}
void set_prev(node* x)
{prev=x;}
};
class list
{
private:
node *head, *current, *tail;
public:
//constructor
list();
void add_node(void);
};
node::node(void)
{
string x;
cout<<"hi"<<endl;
//set front and back null
next=NULL;
prev=NULL;
//write the note
cout<<" what note would you like to write in the node"<<endl;
cin>>x;
note=x;
}
list::list(void){
//start the list pointing to null
head = tail = NULL;
}
void list::add_node(void)
{
//make first node
if(head=0){
head = new node;
cout<<"1"<<endl;
}
//make 2nd node
else if((*head).get_next()==0){
cout<<"2"<<endl;
node* temp;// buffer
temp= new node;
(*head).set_next(temp);
(*head).set_prev(temp);
(*tail).set_next(head);
(*tail).set_prev(head);
}
}
答案 0 :(得分:0)
我认为你在添加节点时遇到了错误。
我看到的问题是,在第一次插入后,你已经正确分配了一个头部,但尾部没有做任何事情。在下一个插入中,因为你的头是有效的,你进入'make second node'代码块,在这里你试图去引用尚未初始化的尾部成员。