Question

我的应用程序中有一个timepicker和daypicker。我需要将这些值传递给另一个对象。但是，由于时间/日期输入为空，因此对象在页面加载时返回undefined。所以我的问题是如何在选择时间/日期之后更新对象中的未定义值。

时间和日期选择器的代码：

        $scope.startTime = function () {
            $scope.time = $filter('date')($scope.time, 'HH:mm:ss');
            $rootScope.time = $scope.time;
            console.log($rootScope.time);
        }

        $scope.startDate = function() {
          $scope.dateStart = $filter('date')($scope.dateStart, 'yyyy-MM-dd');
          $rootScope.startDate = $scope.dateStart;
          console.log($rootScope.startDate);
        }

        $scope.endDate = function() {
          $scope.dateEnd = $filter('date')($scope.dateEnd, 'yyyy-MM-dd');
          $rootScope.endDate = $scope.dateEnd;
          console.log($rootScope.endDate);
        }

        $scope.selectedDay = function () {
         $rootScope.day = $scope.day;
         console.log($rootScope.day);

            }

需要更新值的对象：

             $rootScope.schedule = {
              "@": {
              "let_run": "yes",
              "when_holiday": "ignore_holiday",
              // "begin":"06:30",
              "begin": $rootScope.time,
            },
              "weekdays": {

                 "day": {
                  "@": {
                    "day": $rootScope.day
                    // "day":"0"
                }
              }

              }
            };
            console.log($rootScope.schedule);

Answer 1

通过更新每个功能中的计划对象，我能够解决这个问题。例如：

$scope.startTime = function () {
            $scope.time = $filter('date')($scope.time, 'HH:mm:ss');
            $rootScope.time = $scope.time;
            $rootScope.schedule['@'].begin = $rootScope.time;
            console.log($rootScope.time);
        }

页面加载后传递值

1 个答案: