Question

我有一个看起来像

的数据库

COUNTRY RATES   
AUD     0.5
BRL     1.2
CAD     1.6
CHF     1.4
CZK     2.5

现在我想使用此数组更新费率

$rates = array (
    'AUD' => '0.5',
    'BRL' => '6.2',
    'CAD' => '2.6',
    'CHF' => '7.4',
    'CZK' => '1.5',
 );

我尝试使用此代码

$servername = "localhost";
$username = "root";
$password = "";
$dbname = "eurotoforgein";

// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}

$table = 'rates';


$values = "'" . implode("','", array_values($rates)) . "'";

$sql = "UPDATE `eurotoforgein` SET 'RATES' WHERE rates =  $values";



if(!$result = $conn->query($sql)){ 

die('There was an error running the query [' . $conn->error . ']'); 

}

else{
echo "Data Updated.";
}

但是我明白了运行查询时出错[您的SQL语法中有错误;查看与您的MariaDB服务器版本相对应的手册，以便在''RATES'附近使用正确的语法'WHERE rates ='0.5'，'1.2'，'1.6'，'1.4'，'2.5''在第1行

欢迎任何帮助

Answer 1

这是我的解决方案：

$sql = '';
$rates = array (
    'AUD' => '0.5',
    'BRL' => '6.2',
    'CAD' => '2.6',
    'CHF' => '7.4',
    'CZK' => '1.5',
 );
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "eurotoforgein";

// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}

foreach($rates as $iso=>$rate){
$sql .= "UPDATE `eurotoforgein` SET `RATES`='{$rate}' WHERE COUNTRY = '{$iso}'";
}

if(!$result = $conn->query($sql)){ 

die('There was an error running the query [' . $conn->error . ']'); 

}else{
echo "Data Updated.";
}

Answer 2

您必须逐个更新这些值。这应该会帮助你：

foreach ($rates as $country => $rate) {
  $sql = "update rates set RATES = $rate where COUNTRY = $country";
  // execute
}

如果您想了解更多信息，请查看UPDATE语法：http://dev.mysql.com/doc/refman/5.7/en/update.html

Answer 3

你的SQL查询是这样的：

UPDATE `eurotoforgein` SET 'RATES' WHERE rates = '0.5','6.2','2.6','7.4','1.5'

这不是有效的SQL。

以这种方式构建查询：

$sql = '';
foreach($rates as $country => $value){
    $sql .= "UPDATE `eurotoforgein` SET `rates` = '$value' WHERE `country` =  '$country';";
}

这将创建一个包含多个UPDATE查询的字符串，并且可以在

中执行

1 go，$ conn-＆gt; query（$ sql）;

通过关联数组的值更新mysql

3 个答案: