Question

我目前正在开发一个需要Android应用程序连接到我创建的java服务器的项目。问题是套接字没有初始化。我已将权限添加到AndroidManifest.xml文件

<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.ACCESS_WIFI_STATE" />

我的应用代码如下：

按钮触发：

    View.OnClickListener btnDownloadListener = new View.OnClickListener() {
    @Override
    public void onClick(View v) {
        //Implement download code
        try{
           new ConnectionManager().execute("10.90.181.91" , "21002");
        }catch(Throwable t){

        }

    }
};

ConnectionManager背景功能：

    protected String doInBackground(String... args) {
    try{
        Log.i("Test", "background thread started");
        int port = Integer.parseInt(args[1]);
        InetAddress serverAddr = InetAddress.getByName(args[0]);
        Socket connSock = new Socket(serverAddr, port);
        Log.i("Test", "Created Socket");

    }catch(Throwable t){

    }

   return "";
}

日志输出“background Thread Started”，但从不输出“Created Socket”

服务器代码如下：主要方法

    try{
        ServerSocket serverSocket = null;
        boolean listeningSocket = true;
        try {
            serverSocket = new ServerSocket(21002);
        } catch (IOException e) {
            System.err.println("Could not listen on port: 21002");
        }
        int count = 0;
        while(listeningSocket){             
            try{
                Socket clientSocket = serverSocket.accept();
                new ServerThread(clientSocket).start();                 
            }catch(Throwable t){

            }
        }
        System.out.println("You should not be here");
        serverSocket.close();
    }catch(Throwable t){

    }

ServerThread

public class ServerThread extends Thread {

private Socket socket = null;
private String s;
private  InputStream in;
private  OutputStream out;
BufferedReader is;
BufferedWriter os;
public ServerThread(Socket s) {
    socket = s;
    System.out.println("Thread started: " + socket.getInetAddress());
    try{
         in = socket.getInputStream();
         out = socket.getOutputStream();
         out.flush();
         is = new BufferedReader(new InputStreamReader(in));
         os = new BufferedWriter(new OutputStreamWriter(out));

    }catch(Throwable t){
        t.printStackTrace();
    }       
}
public void run() {
    System.out.println("Thread is running");
    String dataType = "";
    Boolean awaitingTransfer = false;
    try {

        while(true){

            if(in.available() > 0 && !awaitingTransfer){
                dataType = is.readLine();
                System.out.println(dataType);
            }
            if(in.available() > 0 && awaitingTransfer){
                try{
                    ArrayList<SpotCheck> tempList = new ArrayList<SpotCheck>();     
                    while(in.available() > 0){
                        //tempList = (ArrayList<SpotCheck>) in.readObject(); 
                    }

                    ServerMain.manager.applyChanges(tempList);
                    awaitingTransfer = false;
                }catch(Throwable t){
                    t.printStackTrace();
                }

            }
        }
    } catch (Exception e) {
       e.printStackTrace();
       try {

        in.close();
        out.close();
           socket.close();
    } catch (IOException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }

    }

}

}

感谢您的帮助！

Answer 1

作为一名业余编码员，我只是想问你，你能不能像你那样在doInBackground的“catch（）”博客上添加祝酒词

catch(Exception e)
{
   runOnUiThread(new Runnable(){

      @Override
      public void run(){
                     Toast.makeText(getApplicationContext(), e.toString(),
                     Toast.LENGTH_LONG).show();
      }
   });
}

因此它可以更具体地显示您的问题，并且可能更容易处理。但我又不确定它是否有效，我的意思是在asynctask类中使用toast有点棘手。

Android Studio的套接字初始化失败

1 个答案: