Question

我想知道是否有人看到了问题

我正在使用gem will_paginate

我的食谱模型：

class Recipe < ActiveRecord::Base
  belongs_to :user
  has_many :ingredients, dependent: :destroy
  has_many :reviews, dependent: :destroy

  self.per_page = 10
end

我的RecipesController：

class RecipesController < ApplicationController
  skip_before_action :authenticate_user!
  def index
    if params[:search]
      @recipes = Recipe.search(params[:search]).page(params[:page]).order("created_at DESC")
    else
      @recipes = Recipe.all.page(params[:page]).order('created_at DESC')
    end
  end

  def show
    @review = Review.new
    @recipe = Recipe.find(params[:id])
    @user = User.find(@recipe.user_id)
    @full_name = @recipe.user.first_name + " " + @recipe.user.last_name
  end
end

应用/视图/食谱/ index.html.erb：

<%= will_paginate @recipes %>

Answer 1

对于可能关心或有同样问题的人。我找到了解决方案：

我在食谱模型中将 self.per_page = 10 更改为 WillPaginate.per_page = 10 。< / p>

未定义的方法`total_pages＆＃39;对于＃<recipe :: activerecord_relation：0x007fb4045fec58>

1 个答案: