Question

我想将从1开始的数字添加到我的循环中添加的每个元素。

这是代码：

function(data, status){
   var cleanData = $.parseJSON(data);
   var i = 1;
   $.each(cleanData, function(key, value, i) {
      $( "#list" ).append(
        "<div class='large-12 columns'><div class='large-1 columns'>" + (++i) + "</div><div class='large-10 columns'><p> " + value.title + "</p></div><div class='large-1 columns'>" + value.count +"</div></div>" );
        });
    }

我也尝试过(i+1)，但后来我得NaN

所以，最终结果将是这样的：

1 title           count
2 someOtherTitle  count 
3 anotherTitle    count

Answer 1

所以我不完全确定出了什么问题，但也许尝试从函数参数中删除i，因为它在范围内无论如何。也可以使用i ++（读取增量）或设置i = 0.否则你将从2开始。

function(data, status){
   var cleanData = $.parseJSON(data);
   var i = 0;
   $.each(cleanData, function(key, value) {
      $( "#list" ).append(
        "<div class='large-12 columns'><div class='large-1 columns'>" + (i++) + "</div><div class='large-10 columns'><p> " + value.title + "</p></div><div class='large-1 columns'>" + value.count +"</div></div>" );
    });
}

Answer 2

如果您的cleanData是一个列表，请使用$.each()这样的

$.each(cleanData, function(key, value) {
    ...
    ...ns'>" + (key + 1) + "</di...

Answer 3

IF OBJECT_ID('tempdb..#my_table') IS NOT NULL
    DROP TABLE #my_table

CREATE TABLE #my_table
(
    id BIGINT                      IDENTITY PRIMARY KEY
    ,userID                        INT
    ,login_time                    DATETIME
    ,logout_time                   DATETIME
);

DECLARE @MT TABLE
(
     id                            BIGINT
    ,userID                        INT
    ,login_time                    DATETIME
    ,logout_time                   DATETIME
);


DECLARE @DRes TABLE (
    userID          INT,
    logtime         INT
    )

DECLARE @Counter1 INT = 0,
    @login_time1        DATETIME,
    @logout_time1       DATETIME,
    @login_time2        DATETIME

INSERT INTO #my_table VALUES
     (222222, '2016-05-19 01:06:00.000', '2016-05-19 01:10:00.000')
    ,(222222, '2016-05-19 01:12:00.000', '2016-05-19 01:20:00.000')
    ,(333333, '2016-05-24 14:44:00.000', '2016-05-24 14:47:00.000')
    ,(333333, '2016-05-24 14:59:00.000', NULL)
    ,(444444, '2016-05-24 14:48:00.000', '2016-05-24 14:49:00.000')
    ,(444444, '2016-05-24 14:50:00.000', NULL)
    ,(444444, '2016-05-24 14:51:00.000', NULL)
    ,(444444, '2016-05-24 14:53:00.000', '2016-05-24 14:59:00.000')

INSERT INTO @MT
    SELECT * FROM #my_table

;WITH MaxLog 
    AS (
    SELECT userID, MAX(login_time) AS max_login
        FROM @MT
        GROUP BY userID
    ),

DelRec
    AS (
    SELECT ml.userID
        FROM MaxLog ml
        LEFT JOIN @MT mt
            ON ml.userID = mt.userID
        WHERE mt.logout_time IS NULL
            AND ml.max_login = mt.login_time
    )

DELETE mt
    FROM @MT mt
    INNER JOIN
        DelRec dr
        ON mt.userID = dr.userID
    WHERE mt.logout_time IS NOT NULL

;WITH StillIn
    AS (
    SELECT userID, COUNT(*) AS cnt
        FROM @MT
        GROUP BY userID
            HAVING COUNT(*) = 1
    )

UPDATE mt
    SET logout_time = DATEADD(mi,-1,login_time)
        FROM @MT mt
        JOIN StillIn si
            ON si.UserID = mt.UserId

WHILE @Counter1 < (SELECT MAX(id) FROM @MT)
    BEGIN
    SET @Counter1 += 1
    SET @login_time1 = (SELECT login_time FROM @MT WHERE id = @Counter1)
    SET @logout_time1 = (SELECT logout_time FROM @MT WHERE id = @Counter1)
    IF @logout_time1 IS NULL
        BEGIN
        IF @login_time2 IS NULL
            BEGIN
            SET @login_time2 = @login_time1
            END
        END
    ELSE
        BEGIN
        IF @login_time2 IS NULL
            BEGIN
            INSERT INTO @DRes
                SELECT userID, DATEDIFF(mi,@login_time1,@logout_time1)
                FROM @MT
                    WHERE id = @Counter1
            END
        ELSE
            BEGIN
            INSERT INTO @DRes
                SELECT userID, DATEDIFF(mi,@login_time2,@logout_time1)
                FROM @MT
                    WHERE id = @Counter1
            SET @login_time2 = NULL
            END
        END
    END

SELECT userID, SUM(logtime)
    FROM @DRes
    GROUP BY userID

Jquery - 从1开始为每次迭代添加数字

3 个答案: