Question

我有这堂课：

class Player

  attr_accessor :card_pile, :name

  def initialize
    @name = name
    @bust = false
    @card_pile = []
  end

  def bust?
    return @cards.inject(:+) > 21
  end
end

我也将此作为另一个类的开头

def playing_game
    puts "How many players are playing? "
    players_amount = gets.chomp.to_i
      (0...players_amount).each do
        puts ("What is the players name? ")
        @name = gets.chomp
        @players.push(@name)
      end
      @players.each do |each_player|
        @name = Player.new
        while true
          while @name.card_pile.length < 2 do
            new_card = Card.new
            @name.card_pile.push(new_card.value)
          end
          puts(@name.card_pile)
          print @name, "'s turn" "\n"

目前，这将打印出#<Player:0x007fc14984a4b0>'s turn而不是Rich's turn

为什么会这样？我以为我在Player类中创建了一个实例变量，然后实例化了这个类@name = Player.new，然后可以从这里引用它？

Answer 1

这将有助于

def playing_game
  puts 'How many players are playing?'
  players_amount = gets.chomp.to_i
  players_names = (0...players_amount).map do
    puts ("What is the players name? ")
    gets.chomp
  end
  players_names.each do |player_name|
    player = Player.new(player_name)
    while player.card_pile.length < 2 do
      new_card = Card.new
      player.card_pile.push(new_card.value)
    end
    puts player.card_pile
    puts "#{player.name}'s turn"
  end
end

UPD：

您不需要实例变量（例如单个方法中的@name和@players）。
在此代码中，您将遍历玩家名称

@ players.each do | each_player |

=＆GT;

players_names.each do |player_name|

在
的背景下
@name = Player.new

name是一个Player实例创建具有给定名称的播放器将其传递给初始化器：

player = Player.new(player_name)

然后在Player实例上调用您之前创建的名称

puts "#{player.name}'s turn"

在Ruby中使用跨类的变量

1 个答案: