Question

我有以下xml作为名为tblUsers的表的列（Name UserBody）值。

我必须在SQL中使用Xpath读取NewUserType名称，即“SampleUserName”。

<UserTypeAdded xmlns="http://schemas.datacontract.org/2004/07/ABC.Domain.Contract.EventModel" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
        <UserTypeTypeDetails xmlns:a="http://schemas.datacontract.org/2004/07/ABC.Common.Contract">
            <a:Id>550d9a76-3d7d-49f6-9243-f0473d32b123</a:Id>
            <a:Name>Special User Types</a:Name>
        </UserTypeTypeDetails>
        <NewUserType xmlns:a="http://schemas.datacontract.org/2004/07/ABC.Domain.Contract.Base">
            <Id xmlns="http://schemas.datacontract.org/2004/07/ABC.Common.Contract">dfa090ff-9756-42fd-be9b-02ac8c6b123</Id>
            <Name xmlns="http://schemas.datacontract.org/2004/07/ABC.Common.Contract">SampleUserName</Name>
        </NewUserType>
    </UserTypeAdded>

我尝试使用以下声明

   SELECT 
    [UserBody].value('(/UserTypeAdded/NewUserType/Name[1])', 'nvarchar(max)') as UserName 
    FROM tblUsers

但没有运气

Answer 1

您的XML中充满了不同的命名空间，您需要在XQuery中考虑这些命名空间。您可以使用WITH XMLNAMESPACES将前缀映射到名称空间URI，并使用前缀来引用名称空间中的元素，例如：

WITH XMLNAMESPACES 
(
    'http://schemas.datacontract.org/2004/07/ABC.Domain.Contract.EventModel' as utaNs,
    'http://schemas.datacontract.org/2004/07/ABC.Common.Contract' as nameNs
)
SELECT 
    [UserBody].value('(/utaNs:UserTypeAdded/utaNs:NewUserType/nameNs:Name)[1]', 'nvarchar(max)') as UserName 
FROM tblUsers

Answer 2

SELECT @x.value('(/*:UserTypeAdded/*:NewUserType/*:Name)[1]', 'NVARCHAR(MAX)')

Answer 3

您错误地定义了节点，您有：

'(/UserTypeAdded/NewUserType/Name[1])'

您需要指定每个元素的位置：

'(/UserTypeAdded[1]/NewUserType[1]/Name[1])'

或者在parenethesis中包装整个路径并指定其位置：

'(/UserTypeAdded/NewUserType/Name)[1]'

您还需要定义XML命名空间：

-- SAMPLE DATA
DECLARE @tblUsers TABLE (UserBody XML);
INSERT @Tblusers 
VALUES('<UserTypeAdded xmlns="http://schemas.datacontract.org/2004/07/ABC.Domain.Contract.EventModel" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
        <UserTypeTypeDetails xmlns:a="http://schemas.datacontract.org/2004/07/ABC.Common.Contract">
            <a:Id>550d9a76-3d7d-49f6-9243-f0473d32b123</a:Id>
            <a:Name>Special User Types</a:Name>
        </UserTypeTypeDetails>
        <NewUserType xmlns:a="http://schemas.datacontract.org/2004/07/ABC.Domain.Contract.Base">
            <Id xmlns="http://schemas.datacontract.org/2004/07/ABC.Common.Contract">dfa090ff-9756-42fd-be9b-02ac8c6b123</Id>
            <Name xmlns="http://schemas.datacontract.org/2004/07/ABC.Common.Contract">SampleUserName</Name>
        </NewUserType>
    </UserTypeAdded>');

-- QUERY
WITH XMLNAMESPACES
(   'http://schemas.datacontract.org/2004/07/ABC.Domain.Contract.Base' AS a,
    'http://schemas.datacontract.org/2004/07/ABC.Common.Contract' AS x,
    DEFAULT 'http://schemas.datacontract.org/2004/07/ABC.Domain.Contract.EventModel'
)
SELECT *,
        UserBody.value('(/UserTypeAdded/NewUserType/x:Name)[1]', 'nvarchar(max)') as UserName
FROM @TblUsers;

您还可以使用通配符作为名称空间：

SELECT *,
        UserBody.value('(/*:UserTypeAdded/*:NewUserType/*:Name)[1]', 'nvarchar(max)') as UserName
FROM @TblUsers;

Answer 4

试试这个 -

declare @XML xml = '
<UserTypeAdded xmlns="http://schemas.datacontract.org/2004/07/ABC.Domain.Contract.EventModel" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
        <UserTypeTypeDetails xmlns:a="http://schemas.datacontract.org/2004/07/ABC.Common.Contract">
            <a:Id>550d9a76-3d7d-49f6-9243-f0473d32b123</a:Id>
            <a:Name>Special User Types</a:Name>
        </UserTypeTypeDetails>
        <NewUserType xmlns:a="http://schemas.datacontract.org/2004/07/ABC.Domain.Contract.Base">
            <Id xmlns="http://schemas.datacontract.org/2004/07/ABC.Common.Contract">dfa090ff-9756-42fd-be9b-02ac8c6b123</Id>
            <Name xmlns="http://schemas.datacontract.org/2004/07/ABC.Common.Contract">SampleUserName</Name>
        </NewUserType>
    </UserTypeAdded>'


select T.N.value('(/*:UserTypeAdded/*:NewUserType/*:Name)[1]', 'nvarchar(max)') as UserName 
from @XML.nodes('/*:UserTypeAdded') as T(N)

Answer 5

使用以下查询。

     SELECT  [UserBody].value('(/UserTypeAdded/NewUserType/Name)[1]', 'nvarchar(max)') as UserName 
    FROM tblUsers

XPath从sql表列

5 个答案: