我有片段,它有一个searchview和viewpager。我的viewpager有3个片段和每个片段调用适配器。现在要实现searchview,我需要在view pager中调用可见片段的适配器。
SlidingTab(带有searchview和ViewPager的片段):
public class SlidingTab extends Fragment {
private static final String TAG = "TabLayout";
private static String POSITION = "POSITION";
private Context context;
private SearchView searchview;
private Toolbar toolbar ;
/*searching/filteration query*/
private SearchView.OnQueryTextListener OnQuerySearchView = new SearchView.OnQueryTextListener() {
@Override
public boolean onQueryTextSubmit(String arg0) {
// TODO Auto-generated method stub
return false;
}
@Override
public boolean onQueryTextChange(String arg0) {
// TODO Auto-generated method stub
// if (searchCheck) {
Log.i("Recycler query", arg0);
// Fragment frag = new PageAdapter(getChildFragmentManager(),context).getItem(viewPager.getCurrentItem());
PageAdapter adapter = ((PageAdapter) viewPager.getAdapter());
Fragment fragment = adapter.getFragment(viewPager.getCurrentItem());
return false;
}
};
public SlidingTab() {
}
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
View v = inflater.inflate(R.layout.sliding_tab, container, false);
viewPager = (ViewPager) v.findViewById(R.id.view_pager);
viewPager.setOffscreenPageLimit(2);
viewPager.setAdapter(new PageAdapter(getChildFragmentManager(), context));
slidingTab = (TabLayout) v.findViewById(R.id.sliding_tabs);
searchview = (SearchView)v.findViewById(R.id.searchView);
searchview.setOnQueryTextListener(OnQuerySearchView);
return v;
}
SlidingTab.class(实施SearchView)
public class PageAdapter extends FragmentStatePagerAdapter {
private static final String TAG = "PageAdapter";
final int PAGE_COUNT = 3;
private String tabTitles[] = new String[]{"New", "In Progress", "Completed"};
private Context context;
public PageAdapter(FragmentManager fm, Context context) {
super(fm);
this.context = context;
}
@Override
public Fragment getItem(int position) {
Log.d(TAG, "New Instance Created :" + position);
switch (position) {
case 0:
return new JobFragment();
case 1:
return new InProgressJobFragment();
case 2:
return new CompletedJobFragment();
}
return null;
}
@Override
public CharSequence getPageTitle(int position) {
return tabTitles[position];
}
@Override
public int getCount() {
return PAGE_COUNT;
}
}
PageAdapter.class
public class JobAdapter extends RecyclerView.Adapter<JobAdapter.ViewHolder> {
private static final String TAG = "EMPLOYEE ADAPTER";
private static final int VIEW_NORMAL = 0;
private ArrayList<Info> mDataset;
private ArrayList<Info> filterList;
private Context mAct;
public class ViewHolder extends RecyclerView.ViewHolder {
}
}
public void addApplications(ArrayList<Info> candidates) {
}
public void clearApplications() {
}
public JobAdapter(ArrayList<Info> myDataset, Context context) {
this.mDataset = myDataset;
this.mAct = context;
}
@Override
public ViewHolder onCreateViewHolder(ViewGroup parent, int viewType) {
View v = LayoutInflater.from(parent.getContext()).inflate(R.layout.job_card_new, parent, false);
ViewHolder fh = new ViewHolder(v);
return fh;
}
@Override
public void onBindViewHolder(final ViewHolder holder, final int position) {
// }
**// *searching/filtration on List*/**
public void filter(String charText) {
filterList.clear();
if (charText.length() == 0) {
if(mDataset != null) {
filterList.addAll(mDataset);
}
} else {
if (mDataset != null){
for (Info wp : mDataset) {
if(wp.jobNumber !=null){
if(Pattern.compile(Pattern.quote(charText), Pattern.CASE_INSENSITIVE).matcher(wp.jobNumber).find()){
// if (wp.heading1.toLowerCase().contains(charText.toLowerCase())) {
filterList.add(wp);
}}else{
}
this.notifyItemRangeRemoved(0, filterList.size());
}
}
}
notifyDataSetChanged();
}
@Override
public int getItemCount() {
return mDataset.size();
}
}
片段RecyclerView适配器(由视图寻呼机中的每个片段调用并具有searchview过滤方法)
{{1}}
请帮我在viewpager中实现searchview。
答案 0 :(得分:3)
借助上传的代码 我可以告诉你
在你的片段中创建名为search的方法 呼叫适配器过滤方法
public void search(String text)
{
adapter.filter(text)
}
您可以在此行之后检查片段的实例并调用片段的搜索方法
Fragment fragment = adapter.getFragment(viewPager.getCurrentItem());
答案 1 :(得分:0)
我认为最好的设计是使用Activity
作为需要分段的事件的中心“中心”。
所以这就是我要这样做的方式:
首先从侦听器界面开始。这可以声明为Activity
:
static interface QueryListener {
void onQueryChange(String query);
}
Activity获取用于保存侦听器的属性以及用于添加和删除侦听器的方法(声明为synchronized以防止那些令人讨厌的ConcurrentModificationException
:
private List<QueryListener> mQueryListeners = new ArrayList<>();
public synchronized void addQueryListener(@NonNull QueryListener listener) {
// check if the listener was already added
// you could also use a Set instead of a List for this
if (mQueryListeners.contains(listener)) return;
mQueryListeners.add(listener);
}
public synchronized void removeQueryListener(@NonNull QueryListener listener) {
mQueryListeners.remove(listener);
}
Activity也会获得一个方法,可以通过SearchView
的片段调用:
public synchronized void changeQuery(String query) {
for (QueryListener listener : mQueryListeners) {
listener.onQueryChange(query);
}
}
现在使用适配器的片段需要实现QueryListener
并注册/取消注册:
在onCreate()
中的某处添加此行:
((YourActivity) getActivity()).addQueryListener(this);
取消注册onDestroy()
:
@Override
public void onDestroy() {
((YourActivity) getActivity()).removeQueryListener(this);
super.onDestroy();
}
添加QueryListener方法实现:
@Override
public void onQueryChange(String query) {
// if (isVisible()) { if desired
mAdapter.filter(query);
}
注意:您不必拥有片段实现QueryListener
;你可以使用匿名类。但是您必须保留对它的引用,以便稍后可以使用它来调用removeQueryListener()
。
现在只需挂上SearchView
:
@Override
public boolean onQueryTextChange(String query) {
((YourActivity) getActivity()).changeQuery(query);
}
我使用的另一种模式是创建一个用于注册/通知侦听器的专用类。我创建了这个类的单个实例,并在Activity上有一个方法来访问它:
QueryHandler handler = ((YourActivity) getActivity()).getQueryHandler();
// QueryHandler has all the listener properties and methods shown for the Activity
...
handler.changeQuery(query);
或者,您也可以使用Otto等众多开源事件总线包之一在您的片段中传递事件。