Question

这是Observable.from(new Iterable<T>() { @Override public Iterator<T> iterator() { return new Iterator<T>() { @Override public boolean hasNext() { return hasNextPage(currentPageKey); } @Override public T next() { page = getNextPage(currentPageKey); currentPageKey = page.getKey(); return page; } @Override public void remove() { throw new UnsupportedOperationException(); } }; } });表：

presentation

我想在ID PRESENTATIONDAY PRESENTATIONSTART PRESENTATIONEND PRESENTATIONSTARTDATE PRESENTATIONENDDATE 622 Monday 12:00:00 02:00:00 01-05-2016 04-06-2016 623 Tuesday 12:00:00 02:00:00 01-05-2016 04-06-2016 624 Wednesday 08:00:00 10:00:00 01-05-2016 04-06-2016 625 Thursday 10:00:00 12:00:00 01-05-2016 04-06-2016表格中插入availabledate。这是我目前的查询：

schedule

根据insert into SCHEDULE (studentID,studentName,projectTitle,supervisorID, supervisorName,examinerID,examinerName,exavailableID, availableday,availablestart,availableend, availabledate) //PROBLEM STARTS HERE values (?,?,?,?,?,?,?,?,?,?,?,?));检索值availabledate 。例如，如果exavailableID = 2，exavailableID =星期一，availableday = 12 pm，availablestart = 2 pm。

只会在availableend表的PRESENTATIONSTARTDATE到PRESENTATIONENDDATE之间选择日期。

在presentation表格中，它会将presentation，PRESENTATIONDAY和PRESENTATIONDATESTART与PRESENTATIONDATEEND，availableday和availablestart匹配到获取所有可能日期的列表。

这是根据特定日期获取所有可能日期列表的查询：

availableend

此查询结果为：

select 
  A.PRESENTATIONID,
  A.PRESENTATIONDAY,
  A.PRESENTATIONDATESTART+delta LIST_DATE
from 
  PRESENTATION A, 
  (
     select level-1 as delta 
     from dual 
     connect by level-1 <= (
       select max(PRESENTATIONDATEEND- PRESENTATIONDATESTART) from PRESENTATION
     )
  )
where A.PRESENTATIONDATESTART+delta <= A.PRESENTATIONDATEEND
and
  a.presentationday = trim(to_char(A.PRESENTATIONDATESTART+delta, 'Day'))
order by 1,2,3;

它会自动从622 Monday 02-05-2016 12:00:00 ... 622 Monday 30-05-2016 12:00:00 623 Tuesday 03-05-2016 12:00:00 ... 623 Tuesday 31-05-2016 12:00:00 624 Wednesday 04-05-2016 12:00:00 ... 624 Wednesday 01-06-2016 12:00:00 625 Thursday 05-05-2016 12:00:00 ... 625 Thursday 02-06-2016 12:00:00查询中分配日期以插入SELECT表中。但是，每个日期只能使用4次。一旦达到4次，它将进入下一个日期。例如，如果星期一，＆＃39; 02-05-2016＆＃39;到＆＃39; 09-05-2016＆＃39;

如何将这两个查询（schedule和INSERT）合并，以获得如下结果：

SELECT

简而言之，我想根据日期，开始时间和结束时间来使用StudentName projectTitle SupervisorID ExaminerID availableday availablestart availableend availabledate abc Hello 1024 1001 MONDAY 12.00pm 2.00pm 02-05-2016 def Hi 1024 1001 MONDAY 12.00pm 2.00pm 02-05-2016 ghi Hey 1002 1004 MONDAY 12.00pm 2.00pm 02-05-2016 xxx hhh 1020 1011 MONDAY 12.00pm 2.00pm 02-05-2016 jkl hhh 1027 1010 MONDAY 12.00pm 2.00pm 09-05-2016 try ttt 1001 1011 MONDAY 12.00pm 2.00pm 09-05-2016 654 bbb 1007 1012 MONDAY 12.00pm 2.00pm 09-05-2016 gyg 888 1027 1051 MONDAY 12.00pm 2.00pm 09-05-2016 yyi 333 1004 1022 TUESDAY 12.00pm 2.00pm 03-05-2016 fff 111 1027 1041 TUESDAY .. ggg 222 1032 1007 TUESDAY .. .. .. .. hhh 444 1007 1001 TUESDAY 12.00pm 2.00pm 03-05-2016 and so on :)表中的日期列表来插入查询，其中每个日期仅使用4次。谢谢！

Answer 1

我不确定这种语法是否适用于oracle（并且没有好的方法可以检查），但更改插入的选择部分可能会也可能不起作用。

select 
  A.PRESENTATIONID,
  A.PRESENTATIONDAY,
  A.PRESENTATIONDATESTART+delta LIST_DATE
from 
  PRESENTATION A, 
  (
     select level-1 as delta 
     from dual 
     connect by level-1 <= (
       select max(PRESENTATIONDATEEND - PRESENTATIONDATESTART) from PRESENTATION
     )
  ),
  --MIGHT NEED ADDITIONAL LOGIC FOR THE EXAVAILABLEID COMPARISON
  (SELECT count(S.*) as counter FROM SCHEDULE S WHERE S.EXAVAILABLEID=A.ID) C
where A.PRESENTATIONDATESTART+delta <= A.PRESENTATIONDATEEND
and
  a.presentationday = trim(to_char(A.PRESENTATIONDATESTART+delta, 'Day'))
and 
  C.counter<4
order by 1,2,3;

编辑：更改了运营商。曾经> =之前。放置在哪里检查在正确的地方。删除了别名。

EDIT2：将语法更改为计数器select语句是from子句的一部分。

使用子查询插入，根据天数在两个日期之间添加日期[oracle 11g]

1 个答案: