如何在angularjs中转换字符串时间到日期时间

时间:2016-05-24 06:27:23

标签: javascript angularjs

我正在尝试与预定时间匹配当前时间,但我陷入了匹配,因为那些是在字符串中。 这是我的代码

$scope.TimeString = "17:00-21:00,7:00-10:00,9:45-12:00";
 $scope.currentTime = $filter('date')(new Date(), 'HH:mm');
$scope.IsItemAvailable = function (timeString) {

                var tempTimeArray = "";
                tempTimeArray = timeString.split(",");
                for (var i = 0; i < tempTimeArray.length; i++) {
                    var tempTime = tempTimeArray[i];
                    var itemTime = tempTime.split("-")
                    var fromTime = $filter('date')(itemTime[0], 'HH:mm');
                    var toTime = $filter('date')(itemTime[1], 'HH:mm');
                if ($scope.currentTime >= fromTime && $scope.currentTime <= toTime) {
                        $scope.isAvailable = true;
                        break;

                    }
                    else {

                        $scope.isAvailable = false;
                    }
}
it's returning false always.Any please help me to acheive it.

1 个答案:

答案 0 :(得分:0)

如果您可以将时间转换为零填充:09:55,那么您可以将其作为字符串进行比较(如果您没有午夜时间间隔)。

否则,您可以将hh:mm转换为分钟数,然后进行比较:

var cur = $scope.currentTime.split(':');
var from = itemTime[0].split(':');
var to   = itemTime[1].split(':');
cur  =  cur[0]*60+ cur[1];
from = from[0]*60+from[1];
to   =   to[0]*60+  to[1];
if (cur >= from && cur <= to) {
  // available
}

一些DRY解决了:

var times = [$scope.currentTime, itemTime[0], itemTime[1]];
  times.map(interval => interval.split(':'))
       .map(interval => interval[0]*60 + interval[1]);
if (times[0] >= times[1] && times[0] <= times[2]) {
   // available
}