如何隐藏jqgrid内的按钮

Question

我在jqgrid中隐藏我的按钮时出现问题，这是我的代码

{name: 'FitaCorForApproval', index: 'FitaCorForApproval', width: 75,  
  formatter: function (cellvalue, options, rowObject) {
       return '<input type="button" id="hidebuttonID" style ="width: 75px" 
        value="For Approval" onclick="clickme(' + options.rowId + ')" />'
}

感谢

Answer 1

将其添加到格式化程序函数

formatter: function (cellvalue, options, rowObject) {
  var showStyle= '';
  if(!cellvalue)
  {
      showStyle="display:none";
  }

  return '<input type="button" id="hidebuttonID" style ="width: 75px '+showStyle+'" 
        value="For Approval" onclick="clickme(' + options.rowId + ')" />'
}