我希望能够为每个标签使用相同的jqueryui。现在,代码只能在其中一个选项卡中运行......但不会在其余选项卡中运行。关于如何实现这一目标的任何想法?
这是我想要应用于html的jquery:
$(document).ready(function(e) {
// create button and add functionality
$('#add-todo').button({
icons: {
}
}).click(function() {
$('#new-todo').dialog('open');
}); // end click
// build dialog box and add functionality
$('#new-todo').dialog({
modal: true,
autoOpen: false,
buttons : {
"Add task" : function() {
var taskName = $('#task').val();
if (taskName === '') {
return false;
}
var taskHTML = '<li><span class="done"> ✅</span>';
taskHTML += '<span class="delete"> ✄</span>';
taskHTML += '<span class="task"></span></li>';
// convert HTML string to jQuery Object
var $newTask = $(taskHTML);
// add taskname, but make sure HTML is escaped
$newTask.find('.task').text(taskName);
//hide new task
$newTask.hide();
// append to To Do list
$('#todo-list').prepend($newTask);
// show with effect and highlight
$newTask.show('clip',250).effect('highlight',1000);
$(this).dialog('close');
},
"Cancel" : function() {
$(this).dialog('close');
}
},
close: function() {
$('#new-todo input').val(''); /*clear fields*/
}
}); // end dialog
// mark as complete
$('#todo-list').on('click','.done', function() {
var $taskItem = $(this).parent('li');
$taskItem.slideUp(250, function() {
var $this = $(this);
$this.detach();
$('#completed-list').prepend($this);
$this.slideDown();
});
}); // end on
//make both lists sortable
$('.sortlist').sortable({
connectWith : '.sortlist',
cursor : 'pointer',
placeholder : 'ui-state-highlight',
cancel : '.delete,.done'
}); // end sortable
// delete a list item
$('.sortlist').on('click','.delete',function() {
$(this).parent('li').effect('puff', function() {
$(this).remove();
}); // end effect
}); // end on
}); // end ready
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<link rel="stylesheet" href="https://ajax.googleapis.com/ajax/libs/jqueryui/1.11.4/themes/smoothness/jquery-ui.css">
<script src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.11.4/jquery-ui.min.js"></script>
<div id="tabs">
<ul>
<li><a href="#tabs-1">Monday</a></li>
<li><a href="#tabs-2">Tuesday</a></li>
<li><a href="#tabs-3">Wednesday</a></li>
</ul>
<div id="tabs-1">
<div class="container">
<div id="to-do">
<h1>Goals</h1>
<button id="add-todo">Click here to add a goal</button>
<!-- Datepicker -->
<h2 class="header">When do you want to do this?</h2>
<div id="datepicker"></div>
<form id="formscelta" action="Cal.html" method="post">
<input type="hidden" name="datascelta" id="datascelta">
</form>
</div>
<h2>These are the things I said I'd like to accomplish today:</h2>
<ul id="todo-list" class="sortlist">
<li><span class="done">✅</span>
<span class="delete">✄</span>
<span class="task"></span></li>
</ul>
</div>
<div id="completed">
<h2>These are the things I've already completed:</h2>
<ul id="completed-list" class="sortlist">
</ul>
</div>
<div id="new-todo" title="Add to-do item">
<p>
<label for="task">Goal:</label>
<input type="text" name="task" id="task">
</p>
</div>
</div>
<div id="tabs-2"></div>
<div id="tabs-3"></div>
</div>
答案 0 :(得分:1)
目前重用模板的最简单,最常见和最可靠的方法是使用<script>
标记type="text/template"
。
如果浏览器支持不是问题,您可以使用template
代码或template literals
。
也可以将模板作为.html
文件并通过AJAX加载(jQuery load()
,RequireJS text plugin,AngularJS $templateRequest
等支持这有点复杂。
$(document).ready(function(e) {
$('.tab-content').append($('#tabsTemplate').html());
$('#tabs').tabs();
}); // end ready
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<link rel="stylesheet" href="https://ajax.googleapis.com/ajax/libs/jqueryui/1.11.4/themes/smoothness/jquery-ui.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.11.4/jquery-ui.min.js"></script>
<script type="text/template" id="tabsTemplate">
<div class="container">
<div id="to-do">
<h1>Goals</h1>
<button id="add-todo">Click here to add a goal</button>
<!-- Datepicker -->
<h2 class="header">When do you want to do this?</h2>
<div id="datepicker"></div>
<form id="formscelta" action="Cal.html" method="post">
<input type="hidden" name="datascelta" id="datascelta">
</form>
</div>
<h2>These are the things I said I'd like to accomplish today:</h2>
<ul id="todo-list" class="sortlist">
<li><span class="done">✅</span>
<span class="delete">✄</span>
<span class="task"></span>
</li>
</ul>
</div>
<div id="completed">
<h2>These are the things I've already completed:</h2>
<ul id="completed-list" class="sortlist">
</ul>
</div>
<div id="new-todo" title="Add to-do item">
<p>
<label for="task">Goal:</label>
<input type="text" name="task" id="task">
</p>
</div>
</script>
<div id="tabs">
<ul>
<li><a href="#tabs-1">Monday</a>
</li>
<li><a href="#tabs-2">Tuesday</a>
</li>
<li><a href="#tabs-3">Wednesday</a>
</li>
</ul>
<div id="tabs-1" class="tab-content"></div>
<div id="tabs-2" class="tab-content"></div>
<div id="tabs-3" class="tab-content"></div>
</div>
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像Nielsvh在答案中提到的那样,你应该确保在重复使用模板时没有生成
id
或唯一的id
答案 1 :(得分:0)
如果要将内容复制到其他选项卡中,则必须考虑数据的结构以及需要复制的内容。我个人会在javascript中创建对象,然后将其附加到选项卡。您需要特别注意任何ID,并确保它们是唯一的(我在以下代码段中没有做过)。 类似的东西:
$(function(){
var mydiv = $("<div class=\"container\">"+
"<div id=\"to-do\">"+
"<h1>Goals</h1>"+
"<button id=\"add-todo\">Click here to add a goal</button>"+
"<h2 class=\"header\">When do you want to do this?</h2>"+
"<div id=\"datepicker\"></div>"+
"<form id=\"formscelta\" action=\"Cal.html\" method=\"post\">"+
"<input type=\"hidden\" name=\"datascelta\" id=\"datascelta\">"+
"</form>"+
"</div>"+
"<h2>These are the things I said I'd like to accomplish today:</h2>"+
"<ul id=\"todo-list\" class=\"sortlist\">"+
"<li><span class=\"done\">✅</span>"+
"<span class=\"delete\">✄</span>"+
"<span class=\"task\"></span></li>"+
"</ul>"+
"</div>"+
"<div id=\"completed\">"+
"<h2>These are the things I've already completed:</h2>"+
"<ul id=\"completed-list\" class=\"sortlist\">"+
"</ul>"+
"</div>"+
"<div id=\"new-todo\" title=\"Add to-do item\">"+
"<p>"+
"<label for=\"task\">Goal:</label>"+
"<input type=\"text\" name=\"task\" id=\"task\">"+
"</p>"+
"</div>");
for(var i = 1;i <= 3;i++) {
$("#tabs ul").append($("<li/>").append($("<a/>").attr("href","#tabs-"+i).html("tab"+i)));
$("#tabs").append(mydiv.clone().attr("id","tabs-" + i));
}
$("#tabs").tabs();
});
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<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<link rel="stylesheet" href="https://ajax.googleapis.com/ajax/libs/jqueryui/1.11.4/themes/smoothness/jquery-ui.css">
<script src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.11.4/jquery-ui.min.js"></script>
<div id="tabs">
<ul></ul>
</div>
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