Question

我一直在处理一个注册表单，其中有一个从关联数组填充的下拉列表，如下所示：

        **<?php
        **$options = array(
            'cbaringo'    => 'Baringo',
            'cbomet'    => 'Bomet',
            'cbungoma'    => 'Bungoma',
            'cbusia'    => 'Busia',
            'celgeyo'    => 'Elgeyo Marakwet',
            'cmigori'    => 'Migori',**
        ?>**

我想将用户选择的选项插入数据库，如下所示

 **$data = array(
            'scounty' => $this->input->post('counties'),
            'ssubcounty' => $this->input->post('subcounty'),
            'sname' => $this->input->post('dschoolname'),
            'skcpecode' => $this->input->post('dkcpecode'),
            'stelno' => $this->input->post('dtelno'),
            'steampatronname' => $this->input->post('dpatroname'),
            'steampatronemail' => $this->input->post('dpatronemail'),
            'steampatrontelno' => $this->input->post('dpatrontelno'),
            's_password' => $this->input->post('scpassword')
        );**

这样下拉这个下拉：

**echo form_dropdown('counties', $options, 'cdefault');**

以上行按预期显示下拉列表中的选项

        //inserted data into db
        **$this->my_model->insert_data($data);**

然而，插入键而不是关联数组中的值被插入到db中。有什么问题？

Answer 1

您在选择列表中看到的内容与从中传递的值不同

$options = 
           // the value    // what the user sees in the drop down
array(
            'cbaringo'    => 'Baringo',
            'cbomet'    => 'Bomet',
            'cbungoma'    => 'Bungoma',
            'cbusia'    => 'Busia',
            'celgeyo'    => 'Elgeyo Marakwet',
            'cmigori'    => 'Migori',**
        ?>

所以如果他们选择Baringo，那么传递的值应该是cbaringo

将所选选项从下拉列表插入到db codeigniter中

1 个答案: