我正在开发Android网球应用程序，现在我需要在网球比赛中保持打破平局分数的条件。
例如，如果第1组得分为6-6，那么决胜局游戏将从1-1,2-2,3-3开始，依此类推。
或者在其他方面，我如何在网球比赛中实施以下代码的决胜局规则
我正在考虑如何在我的应用程序上保持这种状态，但却无法获得它。我是Java的新手，所以任何帮助都会受到赞赏。
/ * * Player1的方法从下面开始 * * /
assert countBtn1 != null;
countBtn1.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
CountA++;
textViewScore.setText(CountA+"--"+textViewCount1.getText()+"--"+textViewCount2.getText());
if (CountA == 1) {
textViewCount1.setText("15");
} else if (CountA == 2 ) {
textViewCount1.setText("30");
} else if (CountA == 3) {
textViewCount1.setText("40");
}
/*
* After the game is reached to the level of 40-0 for player 1, it checks all the rules of the tennis before finishing the Game
* */
else if (CountA == 4) {
if (CountB == 3 && textViewCount2.getText().toString().equals("40") && textViewCount1.getText().toString().equals("40")) {
textViewCount1.setText("AD");
CountA--;
}
if (CountB == 4 && textViewCount2.getText().toString().equals("40") && textViewCount1.getText().toString().equals("40")) {
textViewCount1.setText("AD");
CountA--;
}
if (CountA == 4 && textViewCount1.getText().toString().equals("40") && textViewCount2.getText().toString().equals("15")) {
textViewCount1.setText("0");
textViewCount2.setText("0");
CountA--;
if(set1 != 7) {
set1 = set1 + 1;
textView1.setText("" + set1);
CountA=0;
}
}
if (CountA == 4 && textViewCount1.getText().toString().equals("40") && textViewCount2.getText().toString().equals("30")) {
textViewCount1.setText("0");
textViewCount2.setText("0");
CountA--;
if(set1 != 7) {
set1 = set1 + 1;
textView1.setText("" + set1);
CountA=0;
}
}
else if (CountA == 4 && textViewCount1.getText().toString().equals("AD") && textViewCount2.getText().toString().equals("40")) {
textViewCount1.setText("0");
textViewCount2.setText("0");
CountA--;
if(set1 != 7) {
set1 = set1 + 1;
textView1.setText("" + set1);
CountA=0;
CountB=0;
}
}
else if (CountA == 4 && textViewCount1.getText().toString().equals("40") && textViewCount2.getText().toString().equals("AD")) {
textViewCount1.setText("40");
textViewCount2.setText("40");
CountA--;
}
else if (CountA == 4 && textViewCount1.getText().toString().equals("40") && textViewCount2.getText().toString().equals("0")) {
textViewCount1.setText("0");
textViewCount2.setText("0");
CountA--;
/*
* The below functions checks the incrementation clause of the game for the sets
* */
if((set1 <= 4 && set4 != 6 && set2 == 0 && set5 == 0)
|| (set1 == 5 && set4 !=7 && set2 == 0 && set5 == 0)
|| (set1 == 5 && set4 == 6 && set2 == 0 && set5 == 0)
// || (set1 == 6 && set4 == 6 && set2 == 0 && set5 == 0)
|| (set1 == 6 && set4 == 5 && set2 == 0 && set5 == 0))
{
set1 = set1 + 1;
// tie1++;
// textViewCount1.setText(""+tie1);
textView1.setText("" + set1);
CountA=0;
if((set1 ==6 && set4 <=4 && set2 == 0 && set5 == 0)|| (set1 ==7 && set4 <= 6 && set2 ==0 && set5 == 0))
{
builder.setMessage("Player 1 wins the 1st set")
.setPositiveButton("OK", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {}
});
AlertDialog theAlertDialog = builder.create();
theAlertDialog.show();
}
}
else if ( set1 == 6 && set4 == 6 && set2 == 0 && set5 == 0){
for (tie1=100; tie1 <= 1; tie1++){
textViewCount1.setText("" + tie1);
CountA=0;
}
}
else if((set2 <= 5 && set5 != 6 && set3 == 0 && set6 == 0)
|| (set2 == 5 && set5 != 7 && set3 == 0 && set6 == 0)
|| (set2 == 6 && set5 == 5 && set3 == 0 && set6 == 0)
|| (set2 == 6 && set5 == 6 && set3 == 0 && set6 == 0))
{
set2 = set2 + 1;
textView2.setText("" + set2);
CountA=0;
if((set1 == 6 && set4 <=4 && set2 ==6 && set5 <=4 && set3 == 0 && set6 == 0) || (set2 ==7 && set5 <= 6 && set3 ==0 && set6 == 0))
{
//builder.setTitle("Game Over");
builder.setMessage("Player 1 won the Match by winning both the Sets")
.setPositiveButton("OK", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
CountA = 0;
CountB = 0;
textView1.setText("0");
textView2.setText("0");
textView3.setText("0");
textView4.setText("0");
textView5.setText("0");
textView6.setText("0");
textViewCount1.setText("0");
textViewCount2.setText("0");
set1 = set2 = set3 = set4 = set5 = set6 = 0;
}
});
AlertDialog theAlertDialog = builder.create();
theAlertDialog.show();
}
else if((set4 ==6 && set1 <=4 && set2 ==6 && set5 <=4 && set3 == 0 && set6 == 0)|| (set2 ==7 && set5 <= 6 && set3 ==0 && set6 == 0))
{
builder.setMessage("Player 1 wins the 2nd Set")
.setPositiveButton("OK", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
}
});
AlertDialog theAlertDialog = builder.create();
theAlertDialog.show();
}
}
else if((set3 <= 4 && set6 != 6)
|| (set3 == 5 && set6 !=7 )
|| (set3 == 5 && set6 == 6 )
|| (set3 == 6 && set6 == 6 )
|| (set3 == 6 && set6 == 5 ))
{
set3 = set3 + 1;
textView3.setText("" + set3);
CountA=0;
if((set3 ==6 && set6 <=4) || (set3 ==7 && set6 <= 6 ))
{
//builder.setTitle("Game Over");
builder.setMessage("Player 1 won the Match by winning both the Sets")
.setPositiveButton("OK", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
CountA = 0;
CountB = 0;
textView1.setText("0");
textView2.setText("0");
textView3.setText("0");
textView4.setText("0");
textView5.setText("0");
textView6.setText("0");
textViewCount1.setText("0");
textViewCount2.setText("0");
set1 = set2 = set3 = set4 = set5 = set6 = 0;
}
});
AlertDialog theAlertDialog = builder.create();
theAlertDialog.show();
}
}
else{
CountA = 0;
}
}
else if (CountA == 5 && textViewCount1.getText().toString().equals("40") && textViewCount2.getText().toString().equals("40")) {
textViewCount1.setText("AD");
textViewCount2.setText("40");
}
}
}
}
);
答案 0 :(得分：0)
如果你有正确的分数实现，如40-0,15-15等，那么将它镜像到处理tiebreak的辅助方法应该是直截了当的。
由于你的代码非常详细，我无法告诉你如何逐行完成，只是将tiebreak视为另一个附加集，并以与实现集合相同的方式实现它：
即。有一个counterA和一个counterB如果玩家A赢得一个点增加他的计数器，否则增加B的计数器 - 并且一旦玩家的一个计数器达到让他赢得{{ 1}}（例如A获胜的条件是： tiebreak和counterA == 6 或 counterA - counterB >= 2（通过{{1 }}，counterA == 7） - 如果我能正确记住网球规则的话）
然后只有在设定分数达到6-6时才调用您的if方法（但是您选择执行此检查很好）并将else if的获胜者返回到处理集合功能。