Question

我遇到了一些给我的代码有问题。它不是应该连接的行。我从3个表中拉出来选择要连接的行。我有一个Comment，WorkOrderT和WorkMaterial_nonFiltered表。

Comment表显然有注释，并且链接到WorkMaterial_nonFiltered表。 WorkMaterial_nonFiltered表连接到工作订单ID所在的WorkOrderT表。

我正在尝试使用工作订单ID来获取该工单的所有注释，并将它们全部连接到每个工单ID的一行中。这是我目前拥有的代码：

select 
    wo.WOId as ID,
    STUFF(cast((select distinct '; ' + c.comments
                from working.Comment c
                where c.Instance_InstanceId = wm.id
                for xml path(''), type) as varchar(max)), 1, 1, ' ') as MaterialComments
from 
    working.WorkOrderT wo
left join 
    working.WorkMaterial_nonFiltered wm on wm.WorkOrder = wo.WOId
where 
    wo.WOId = '00559FB6-4DD2-4762-8DE1-8D1B13962AED' 
order by     
    [MaterialComments]

当我运行时，我得到了11行。第一个的MaterialComments为NULL，其他人的数据为NULL。我并不关心WorkOrderID Comments 00559FB6-4DD2-4762-8DE1-8D1B13962AED 5/17 caj in transit; expected delivery on 5/18 per ups 1Z25AR580319345668 00559FB6-4DD2-4762-8DE1-8D1B13962AED 5/18 caj updated esd on 6/17 per vendor site 00559FB6-4DD2-4762-8DE1-8D1B13962AED 5/17 caj allocated to ship 00559FB6-4DD2-4762-8DE1-8D1B13962AED 5/17 caj updated esd on 5/27 per vendor site 00559FB6-4DD2-4762-8DE1-8D1B13962AED 5/18 caj processed; no udpated delivery date per estes Tracking #/BOL #: 3SNS31780960 00559FB6-4DD2-4762-8DE1-8D1B13962AED 5/18 caj processed; no updated delivery date per ups 1Z39ER600354622348 008FC1D1-D6A6-4E48-A69F-168DBF8D215A Jun 25 2015 10:22AM;dlb223;6/25 dlb 1Z4370490304215160 to be dlv'd today 008FC1D1-D6A6-4E48-A69F-168DBF8D215A Jun 8 2015 1:11PM;klh323;6/8 klh Reserved to meet 06/30 requested delivery date 008FC1D1-D6A6-4E48-A69F-168DBF8D215A Jun 25 2015 10:23AM;dlb223;6/23/2015 008FC1D1-D6A6-4E48-A69F-168DBF8D215A Jun 25 2015 10:23AM;dlb223;6/5 dlb 1Z4370490304215937 to be dlv'd today 008FC1D1-D6A6-4E48-A69F-168DBF8D215A Jun 25 2015 10:24AM;dlb223;6/25 dlb 1Z4370490304216445 to be dlv'd today 00910B84-486C-4AD4-9B1E-5F8D8B42C841 5/12 jad IN TRANSIT; EXPECTED DELIVERY 5/12 PER UPS 1Z750WA20313280446 00910B84-486C-4AD4-9B1E-5F8D8B42C841 4/29 jad IN TRANSIT; EXPECTED DELIVERY 4/29 PER UPS 1Z39ER600354244542行，除非它是导致问题的原因，而是我真正需要连接的其他行，由“;”分隔。我已经尝试过一步一步建立这个，但我无法弄清楚为什么我总是得到11行而不仅仅是1.我已经调查了以下其他问题来尝试寻找解决方案：

Concatenate many rows into a single text string?

Concatenate Rows using FOR XML PATH() from multiple tables

How to create a SQL Server function to “join” multiple rows from a subquery into a single delimited field?

How to make a query with group_concat in sql server

String Aggregation in the World of SQL Server

到目前为止，我无法从这些链接中获得任何建议，我仍然可以获得11行而不是1行连接。

修改

以下是我在表格中提供的一些示例数据:(请注意如何使这个实际的表格对于草率的格式化而言抱歉）

WorkOrderID                                     Comments
00559FB6-4DD2-4762-8DE1-8D1B13962AED            5/17 caj in transit; expected delivery on 5/18 per ups 1Z25AR580319345668; 5/18 caj updated esd on 6/17 per vendor site; 5/17 caj allocated to ship; 5/17 caj updated esd on 5/27 per vendor site; 5/18 caj processed; no udpated delivery date per estes Tracking #/BOL #:    3SNS31780960; 5/18 caj processed; no updated delivery date per ups 1Z39ER600354622348  
008FC1D1-D6A6-4E48-A69F-168DBF8D215A            Jun 25 2015 10:22AM;dlb223;6/25 dlb 1Z4370490304215160 to be dlv'd today; Jun  8 2015  1:11PM;klh323;6/8 klh Reserved to meet 06/30 requested delivery date; Jun 25 2015 10:23AM;dlb223;6/23/2015; Jun 25 2015 10:23AM;dlb223;6/5 dlb 1Z4370490304215937 to be dlv'd today; Jun 25 2015 10:24AM;dlb223;6/25 dlb 1Z4370490304216445 to be dlv'd today  
00910B84-486C-4AD4-9B1E-5F8D8B42C841            5/12 jad IN TRANSIT; EXPECTED DELIVERY 5/12 PER UPS 1Z750WA20313280446; 4/29 jad IN TRANSIT; EXPECTED DELIVERY 4/29 PER UPS 1Z39ER600354244542

结果我想看起来像这样:(我再也不知道如何把它作为一个表格）

{{1}}

我希望这能让我更加清楚我想要实现的目标。

Answer 1

我最终使用传递查询到链接服务器。这就是实际问题所在。数据从链接服务器返回。一旦我弄明白，我就能得到我需要的结果。现在我有一个使用for xml的很长的传递查询，并按照我需要的方式给出了WOID的注释。

Answer 2

明确要求元素中的文本节点，而不是元素。

select 
    wo.WOId as ID,
    (select distinct '; ' + c.comments as "text()"
                from working.Comment c
                where c.Instance_InstanceId = wm.id
                for xml path(''), type) as "MaterialComments"
from 
    working.WorkOrderT wo
left join 
    working.WorkMaterial_nonFiltered wm on wm.WorkOrder = wo.WOId
where 
    wo.WOId = '00559FB6-4DD2-4762-8DE1-8D1B13962AED' 
order by     
    [MaterialComments]

对于xml路径，不连接SQL Server中的SQL查询中的行

2 个答案: