Question

我有阵列：

[ [ '245', '0', '0.0100', '245,0,0.01' ],
  [ '245', '1', '0.0100', '245,1,0.01' ],
  [ '208', '0', '0.0300', '208,0,0.03' ],
  [ '208', '0', '0.0500', '208,0,0.05' ],
  [ '208', '0', '0.0600', '208,0,0.06' ] ]

我需要通过[0]和[1]单元获取唯一数组像这样：

[ [ '245', '0', '0.0100', '245,0,0.01' ],
  [ '245', '1', '0.0100', '245,1,0.01' ],
  [ '208', '0', '0.0600', '208,0,0.06' ] ]

请帮助/

Answer 1

使用lodhash uniqBy() 方法

var data = [
  ['245', '0', '0.0100', '245,0,0.01'],
  ['245', '1', '0.0100', '245,1,0.01'],
  ['208', '0', '0.0300', '208,0,0.03'],
  ['208', '0', '0.0500', '208,0,0.05'],
  ['208', '0', '0.0600', '208,0,0.06']
];

console.log(
  _.uniqBy(data, function(v) {
    return v[0] + ' ' + v[1];
  })
)

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.13.0/lodash.js"></script>

Lodash uniqBy多个数组？

1 个答案: