我在下面发现这个奇怪的错误
json.c:81:19: warning: missing terminating " character [enabled by default]
json.c:81:3: error: missing terminating " character
json.c:82:32: error: expected ‘,’ or ‘;’ before ‘:’ token
json.c:90:22: warning: missing terminating " character [enabled by default]
json.c:90:21: error: missing terminating " character
CODE:
int main()
{
char * string = "{
"sender" : "joys of programming",
"receiver": [ "123",
"345",
"654",
"432"
]
}";
printf("JSON string: %sn", string);
json_object * jobj = json_tokener_parse(string);
json_parse(jobj);
return 0;
}
我理解错误大约是char * string
行。但不知道如何解决它。
答案 0 :(得分:2)
你必须:
"
char,因为它是一个用于定义a的特殊字符
C-String文字。""
为每一行定义每一行作为单个C字符串因此,生成的代码是
char * string = "{"
"\"sender\" : \"joys of programming\","
"\"receiver\": [ \"123\","
"\"345\","
"\"654\","
"\"432\""
"]"
"}";
答案 1 :(得分:1)
在引号内使用引号时,需要使用转义字符。
char * string = "{ "
"\"sender\" : \"joys of programming\","
"\"receiver\": [ \"123\","
"\"345\","
"\"654\","
"\"432\""
"]"
"}";
这样就可以了。