Question

我想创建变量：在$

之前提取数字的数字

Name      | Number
abc1/12 $ | 12
12av 12$  | 12
114$-bgv  | 114

我有一个问题：

select Name, substring(Name FROM '%#"[0-9]+#"$%' FOR '#') as Number
from table;

但它返回：

Name      | Number
abc1/12 $ | 
12av 12$  | 2
114$-bgv  | 4

有什么想法吗？

Answer 1

使用regexp_matches()：

select
  (regexp_matches(Name,  '^(.*[^\d]+){0,1}(\d+)\$'))[2] as Number
from (
  select 'abc1/12$' as Name
  union select '12av 12$'
  union select 'bgv-114$'
  union select '124$'
) t

或substring()

select
  coalesce(substring(Name FROM '.*[^\d]+(\d+)\$'), '') ||
  coalesce(substring(Name FROM '^(\d+)\$'), '') as Number
from (
  select 'abc1/12$' as Name
  union select '12av 12$'
  union select 'bgv-114$'
  union select '124$'
) t

Postgresql：在给定子字符串之前提取数字

1 个答案: