Question

我真的不知道如何解决这个问题。每次我将这行代码添加到我的php文档中时，页面都会变成空白。有没有人遇到过这个问题？

它在一张桌子里。显然它是 checked_id [] 数组。不知道如何修复它，它只会导致页面在添加时变为空白。

<td align="center"><input type="checkbox" name='.checked_id[];.' class="checkbox" value='.$row["id"].'</td>

这是整个街区。

 $output .= '  
<form name="bulk_action_form" action="delete_multiple.php" method="post" onSubmit="return delete_confirm();"/>
      <div class="table-responsive">  
           <table class="table table-bordered">  
                <tr>  

                     <th width="10%">Id</th>  
                     <th width="40%">Name</th>  
                     <th width="40%">Email</th>  
                     <th width="40%">Address</th>  
                     <th width="10%">phoneNumber</th>  
                     <th width="10%">appointmentTime</th> 
                     <th width="10%">appointmentDate</th> 
                     <th width="50%">message</th> 
                     <th width="10%">delete</th>
                     <th><input type="checkbox" name="select_all" id="select_all" value=""/></th>
                </tr>';  



                             if(mysqli_num_rows($result) > 0)  
                             {  
                                  while($row = mysqli_fetch_array($result))  
                                  {  
                                       $output .= '  




                <tr>  

                     <td>'.$row["id"].'</td>
                     <td class="name" data-id1="'.$row["id"].'" contenteditable>'.$row["name"].'</td>  
                     <td class="email" data-id2="'.$row["id"].'" contenteditable>'.$row["email"].'</td>
                     <td class="address" data-id2="'.$row["id"].'" contenteditable>'.$row["address"].'</td>  
                     <td class="phoneNumber" data-id2="'.$row["id"].'" contenteditable>'.$row["phoneNumber"].'</td>  
                     <td class="appointmentTime" data-id2="'.$row["id"].'" contenteditable>'.$row["appointmentTime"].'</td>  
                     <td class="appointmentDate" data-id2="'.$row["id"].'" contenteditable>'.$row["appointmentDate"].'</td>
                     <td class="message" data-id2="'.$row["id"].'" contenteditable>'.$row["message"].'</td>
                     <td><button type="button" name="delete_btn" data-id3="'.$row["id"].'" class="btn btn-xs btn-danger                             btn_delete">Delete</button></td>
                     <td><input type="checkbox" name="'.checked_id[].'" class="checkbox" value="'.$row["id"].'"/></td>
                </tr>  
           ';  
      }                                   

 }  
 else  
 {  

      $output .= '<tr><td colspan="4">Data not Found</td></tr>';  
 }  


 $output .= '</table>  
      </div></form>';  
 echo $output;  
 ?>

Answer 1

结构不合理：

缺少关闭代码
缺少引号

像这样使用：

<input type="checkbox" name="'.checked_id[].'" class="checkbox" value="'.$row["id"].'"/></td>
                            ^            ^ ^ ^                        ^              ^^^

Answer 2

首先，你必须将name='.checked_id[];.' class="checkbox" value='.$row["id"]. PHP变量转换成HTML，你不能只写出自己的名字，因为HTML不明白。以下是第一行中的示例，您在大多数代码中都给出了相同的示例。你的代码：

name='<?php echo checked_id[]; ?>' class="checkbox" value='<?php echo $row["id"]; ?>'

应该如何：

checked_id[]

另一件事，我认为name="<?php echo $somevariable; ?>"应该是一个数组索引，你不能把它留空。如果我错了，请纠正我，并在整个页面中使用此示例，因为要显示PHP变量，您必须打开HTML并在此处回显您的变量<?php $output .= ""; ?> <form name="bulk_action_form" action="delete_multiple.php" method="post" onSubmit="return delete_confirm();"/> <div class="table-responsive"> <table class="table table-bordered"> <tr> <th width="10%">Id</th> <th width="40%">Name</th> <th width="40%">Email</th> <th width="40%">Address</th> <th width="10%">phoneNumber</th> <th width="10%">appointmentTime</th> <th width="10%">appointmentDate</th> <th width="50%">message</th> <th width="10%">delete</th> <th><input type="checkbox" name="select_all" id="select_all" value=""/></th> </tr>'; <?php if(mysqli_num_rows($result) > 0) { while($row = mysqli_fetch_array($result)) { $output .= ' ?> <tr> <td><?php echo $row["id"]; ?></td> <td class="name" data-id1="<?php echo $row["id"]; ?>" contenteditable><?php echo $row["name"]; ?></td> <td class="email" data-id2="<?php echo $row["id"]; ?>" contenteditable><?php echo $row["email"]; ?></td> <td class="address" data-id2="<?php echo $row["id"]; ?>" contenteditable><?php echo $row["address"]; ?></td> <td class="phoneNumber" data-id2="<?php echo $row["id"]; ?>" contenteditable><?php echo $row["phoneNumber"]; ?></td> <td class="appointmentTime" data-id2="<?php echo $row["id"]; ?>" contenteditable><?php echo $row["appointmentTime"]; ?></td> <td class="appointmentDate" data-id2="<?php echo $row["id"]; ?>" contenteditable><?php $row["appointmentDate"]; ?></td> <td class="message" data-id2="<?php echo $row["id"]; ?>" contenteditable><?php echo $row["message"]; ?></td> <td><button type="button" name="delete_btn" data-id3="<?php echo $row["id"]; ?>" class="btn btn-xs btn-danger btn_delete">Delete</button></td> <td align="center"><input type="checkbox" name="<?php echo $checked_id[]; ?>" class="checkbox" value="<?php echo $row["id"]; ?>"</td> </tr> }

试试这个：

res.status(206);

PHP / HTML行导致页面变为空白

2 个答案: