如何级联三个下拉列表?
我有一个带有三个下拉列表的页面模板,选项html标签的值由mysql动态填充。我想在第3个下拉列表中显示选项取决于第二个下拉列表,它将显示第二个下拉列表中的选项取决于在第一个下拉列表中选择的选项。
E.g. (1) Job position (2) location (3) a dropdown with "Yes" and "No" option. (Job Position -> Location -> Yes/No (dropdown))
我尝试了一些JS脚本,但我没有运气正确。请帮助我,我差不多花了一个星期的时间:(
PHP代码段:
<?php
ob_start();
global $wpdb;
$query_position = "";
$list_position = "";
$result_position = "";
$query_locations = "";
$list_location = "";
$result_location = "";
$query_processed = "";
$list_processed = "";
$result_processed = "";
$query_position = $wpdb->get_results('SELECT DISTINCT position FROM resume_databank ORDER BY position ASC', OBJECT);
$query_locations = $wpdb->get_results('SELECT DISTINCT hiring_location FROM resume_location ORDER BY hiring_location ASC', OBJECT);
$query_processed = $wpdb->get_results('SELECT DISTINCT process_resume FROM resume_databank ORDER BY process_resume ASC', OBJECT);
?>
<div id="">
<form action='' method='post' name='resumeDatabank' id='resumeDatabank'>
<div class="div-select">
<label for="list_position" id="#ddress_search LABEL">Position</label>
<br/>
<select name="list_position" id="filterbypostion">
<option name="default" class="filter_by" selected="selected" value="Select by Position">Select by Position</option>
<?php
foreach($query_position as $option){
if(isset($_POST['list_position']) && $_POST['list_position'] == $option->position)
echo '<option name="list_position" class="filter_by" selected value="'. $option->position .'">'. $option->position .'</option>';
else
echo '<option name="list_position" class="filter_by" value="'. $option->position .'">'. $option->position .'</option>';
};
?>
</select>
</div>
<div class="div-select">
<label for="list_location" id="#ddress_search LABEL">Location</label>
<br/>
<select name="list_location" id="filterbylocation">
<option name="default" class="filter_by" selected="selected" value="Select by Location">Select by Location</option>
<?php
foreach($query_locations as $option){
if(isset($_POST['list_location']) && $_POST['list_location'] == $option->hiring_location)
echo '<option name="list_location" class="filter_by" selected value="'. $option->hiring_location .'">'. $option->hiring_location .'</option>';
else
echo '<option name="list_location" class="filter_by" value="'. $option->hiring_location.'">'. $option->hiring_location .'</option>';
};
?>
</select>
</div>
<div class="div-select">
<label for="list_processed" id="#ddress_search LABEL">Processed</label>
<br/>
<select name="list_processed" id="filterbyprocessed">
<option name="default" class="filter_by" selected="selected" value="Select by Processed">Select by Processed</option>
<?php
foreach($query_processed as $option){
if(isset($_POST['list_processed']) && $_POST['list_processed'] == $option->processed_option)
echo '<option name="list_processed" class="filter_by" selected value="'. $option->processed_option .'">'. $option->processed_option .'</option>';
else
echo '<option name="list_processed" class="filter_by" value="'. $option->processed_option.'">'. $option->processed_option .'</option>';
};
?>
</select>
</div>
<div class="div-input">
<input type="submit" value="Search" class="div-input-submit"/>
</div>
</form>
</div>
答案 0 :(得分:0)
以下是我的示例(根据您的示例进行调整),我希望能提供帮助:
<?
mysql_connect('localhost','root','');
mysql_select_db('test');
if(!empty($_POST['location'])) {
$qry = mysql_query("SELECT * FROM location");
echo '<select id="location">';
while($rw = mysql_fetch_row($qry)) {
echo '<option value="'.$rw[1].'">'.$rw[1].'</option>';
}
echo '</select>';
} else {
$query = mysql_query("SELECT * FROM job");
echo '<select id="job">';
while($row = mysql_fetch_row($query)) {
echo '<option value="'.$row[0].'">'.$row[1].'</option>';
}
echo '</select>';
}
?>
<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$("#job").bind("change", function(){
$.post("index.php",{'location': $('#job').val()},function(data){
$('#location').remove();
$("#job").after(data);
});
});
});
</script>