我有这个应用程序,我可以将文件上传到特定的类别或子类别。它工作正常,但我遇到的问题是当我试图仅为特定用户显示选择值时,对于特定的父类别,它只显示存储在数据库中的所有值。
views.py
class AddDocumentView(LoginRequiredMixin, SuccessMessageMixin, CreateView):
login_url = reverse_lazy('users:login')
form_class = FileUploadForm
template_name = 'docman/forms/add-document.html'
success_url = reverse_lazy('docman:index')
success_message = 'Document was successfully added'
def form_valid(self, form):
profile = form.save(commit=False)
profile.user = self.request.user
return super(AddDocumentView, self).form_valid(form)
forms.py
class FileUploadForm(forms.ModelForm):
file = forms.FileField()
class Meta:
model = Document
exclude = ('user',)
fields = [
'file',
'slug',
'category',
]
def __init__(self, user=None, **kwargs):
super(FileUploadForm, self).__init__(**kwargs)
if user:
self.fields['category'].queryset = Category.objects.filter(user_id=user.id, parent_id=None)
我已经尝试过类似问题的解决方案,这就是我如何做到这一点,但它仍然没有被用户过滤,我无法弄清楚如何通过父ID过滤它。对我做错了什么想法?感谢任何帮助,如果需要,我可以提供更多信息。
-----------------解决方案更新-----------------
谢谢@solarissmoke我能够获取表单的用户信息。然后我做了同样的事情来使用kwargs从url捕获parent_id。
views.py
# Override the view's get_form_kwargs method to pass the user and/or pk to the form:
def get_form_kwargs(self):
pk = self.kwargs['pk']
kwargs = super(AddDocumentView, self).get_form_kwargs()
kwargs['user'] = self.request.user
# Check if category exists with pk, otherwise none
if Category.objects.filter(parent_id=pk):
kwargs['pk'] = pk
else:
kwargs['pk'] = None
return kwargs
然后我将额外的文章(pk)添加到 init
forms.py
def __init__(self, user=None, pk=None, **kwargs):
super(FileUploadForm, self).__init__(**kwargs)
if user:
self.fields['category'].queryset = Category.objects.filter(user=user, parent_id=pk)
答案 0 :(得分:1)
您的表单需要user
参数,但您没有提供参数,因此user
始终为None
。您可以覆盖视图get_form_kwargs
method以将用户传递到表单:
class AddDocumentView(LoginRequiredMixin, SuccessMessageMixin, CreateView):
def get_form_kwargs(self):
kwargs = super(AddDocumentView, self).get_form_kwargs()
kwargs['user'] = self.request.user
return kwargs
您的FileUploadForm
现在将获取用户对象,并会相应地过滤结果。