我在这个bash脚本中遇到了上述错误：
line 21: syntax error near unexpected token `done'
line 21: ` done'
我在其他问题中寻找像这里提到的空循环，我什么都没看到。知道为什么吗？
#!/bin/bash
while read -a line; do
:
for word in ${array[*]}; do
let last_index=${#arr[*]}-1
bool=false
if [[ $word != [1-9]* && bool==true ]]; then
echo -n $word
else if [[ $word != [1-9]* && bool==false ]]; then
bool=false
echo -n "_$word"
else if [[ $word == ${array[last_index]} ]]; then
date=${word//./ }
for element in $date; do
element=${element/0}
done
echo " $date"
else echo -n " $word "
fi
done
done
答案 0 :(得分：3)
您只有一个 Array
(
[0] => Array
(
[id] => 1
[parent] => 0
[value] => hello
[child] => Array
(
[0] => Array
(
[id] => 2
[parent] => 1
[value] => hi
[child] => Array
(
[0] => Array
(
[id] => 3
[parent] => 2
[value] => whats up
[child] => Array
(
[0] => Array
(
[id] => 4
[parent] => 3
[value] => yow
)
)
)
[1] => Array
(
[id] => 6
[parent] => 2
[value] => nice
)
)
)
[1] => Array
(
[id] => 5
[parent] => 1
[value] => hellow
)
)
)
[1] => Array
(
[id] => 7
[parent] => 0
[value] => great
)
，其中有三个fi语句，因此不需要if。您需要使用done而不是elif。
else if或者您需要更多地缩进第二个和第三个#!/bin/bash
while read -a line; do
:
for word in ${array[*]}; do
let last_index=${#arr[*]}-1
bool=false
if [[ $word != [1-9]* && bool==true ]]; then
echo -n $word
elif [[ $word != [1-9]* && bool==false ]]; then
bool=false
echo -n "_$word"
elif [[ $word == ${array[last_index]} ]]; then
date=${word//./ }
for element in $date; do
element=${element/0}
done
echo " $date"
else echo -n " $word "
fi
done
done
语句，并添加缺少的if标记。
顺便说一句，冒号命令是无害的，但在此脚本中没有任何用处。