Question

我在rails（4.0）中构建了一个新项目，我对如何在控制器中获取变量提出了疑问。我有2个模型，它们具有多对多关系，即引线和属性。接下来，我的用户模型通过模型位置通过一对多链接。

用户有一个或多个位置，位置有一个或多个属性。 Lead有很多属性，属性有很多潜在客户。

现在，在我的用户控制器中，我尝试拥有属于某个用户的所有潜在客户。有人可以帮助我如何在我的控制器中获取此功能吗？

此刻我有这样的事情，这显然是不正确的。

def operator_leads
  if  current_user
    @user = User.find(current_user.id)
  else
    @user = nil
  end
  @leads = @user.property.each do |k|
    leads << k.leads
  end
end

更新：我当前的模特

class Location < ActiveRecord::Base
  has_many :properties, :dependent => :destroy
  belongs_to :user, :counter_cache => true
end

class Property < ActiveRecord::Base
  include Tokenable
  belongs_to :location
  has_one :user ,:through => :location
  has_many :leads, :through => :lead_properties
  has_many :lead_properties, :dependent => :delete_all
end

class User < ActiveRecord::Base  
   include Tokenable
  devise :database_authenticatable, :registerable, :confirmable,
         :recoverable, :rememberable, :trackable, :validatable
  has_many :locations, :dependent => :destroy 
  has_many :blogs
  has_many :admin_leads, :class_name => 'Lead', :foreign_key => 'admin_user_id'
  has_many :leads, :through => :properties
end

class Lead < ActiveRecord::Base
    has_many :properties, :through => :lead_properties
    has_many :lead_properties
    belongs_to :admin_user, :class_name => "User"
    has_many :users, :through => :properties
end

class LeadProperty < ActiveRecord::Base
    belongs_to :lead
    belongs_to :property 
    accepts_nested_attributes_for :lead
end

Answer 1

使用嵌套的has_many :through通过位置定义具有许多属性的用户：

class User
  has_many :locations
  has_many :properties, through: :locations
  has_many :leads, through: :properties
end

class Location
  belongs_to :user
  has_many :properties
  has_many :leads, through: :property
end

class Property
  belongs_to :location
  has_many :leads
end

然后定义你的控制器：

def operator_leads
  @user = current_user  # You can use current_user in the view to avoid defining @user here.
  @leads = current_user.leads
end

文档：http://guides.rubyonrails.org/association_basics.html#the-has-many-through-association

如何在控制器中获取变量，在轨道中获取多对多和一对多

1 个答案: