考虑以下示例:
WidgetObservable.text(searchView).debounce(250, TimeUnit.MILLISECONDS).flatMap(new Func1<OnTextChangeEvent, Observable<List<String>>>() {
@Override
public Observable<List<String>> call(OnTextChangeEvent onTextChangeEvent) {
String s = onTextChangeEvent.text().toString();
return provider.getGeocodeObservable(s, 5).flatMap(new Func1<List<Address>, Observable<String>>() {
@Override
public Observable<String> call(List<Address> addresses) {
return Observable.from(addresses).map(new Func1<Address, String>() {
@Override
public String call(Address address) {
String addresss = address.getAddressLine(0); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
String city = address.getLocality();
//String state = address.getAdminArea();
String country = address.getCountryName();
return String.format("%s, %s, %s", addresss, city, country);
}
});
}
}).collect(new Func0<List<String>>() {
@Override
public List<String> call() {
return new ArrayList<String>();
}
}, new Action2<List<String>, String>() {
@Override
public void call(List<String> strings, String s) {
strings.add(s);
}
}).subscribeOn(Schedulers.io());
}
}).observeOn(AndroidSchedulers.mainThread()).subscribe(new Subscriber<List<String>>() {
@Override
public void onCompleted() {
}
@Override
public void onError(Throwable e) {
Log.e("MapsActivity", "What?", e);
}
@Override
public void onNext(List<String> strings) {
Log.d("MapsActivity", "works " + strings);
adapter.clear();
adapter.addAll(strings);
adapter.notifyDataSetChanged();
searchView.showDropDown();
}
});
在这里,我观察自动完成视图上的文本更改,并使用Android-ReactiveLocation对其进行操作以获取相关的地址建议。它很好地工作,直到在geocode observable上发生错误,导致在最终订阅者上调用onError。自从发生此错误以来,WidgetObservable将不再发出事件。
如何修复它以便onError不会导致Observable停止发出文本更改事件以便整个流程继续发生?
顺便说一句,我是Reactive编程和RXJava的新手,所以对我的代码的任何改进建议都会受到欢迎:)答案 0 :(得分:3)
您可以尝试使用可观察地理编码的OnErrorReturn
运算符,即
provider.getGeocodeObservable(s, 5)
.onErrorReturn(new Func1<Throwable, List<String>>() {
@Override
public String call(Throwable throwable) {
return Arrays.asList(new String[]{});
}
})